Given ---›
y = -3
&
y = x - 0.8
So,
=> x = y + 0.8
=> x = -3 + 0.8
=> x = -2.2
Therefore, the best approximation for the solution to this system of equations is = (–2.2, –3)
Answer:
Step-by-step explanation:
This is correct, except that if you have two variables you will need two equations. The other equation (the easy one!) was x+ y = 100, from which you might want to solve for y = 100-x, and substitute into the other equation to get:
.30x + .02(100-x) = .04(100)
.30x + 2 - .02x = 4
.28x = 2
x = 2/.28 = 50/7 or approximately 7.14 gallons of cream
100-x = 92 6/7 or approximately 92.86 gallons of 2%
R^2 at SCC
answer: 6 is the greatest number of snack bags that Destiny can make. Step-by-step
Step-by-step explanation:
The first gift is a box of 18 chocolate candy bars, and the second gift is a pack of 12 cookies.
In a large population, 61% of the people are vaccinated, meaning there are 39% who are not. The problem asks for the probability that out of the 4 randomly selected people, at least one of them has been vaccinated. Therefore, we need to add all the possibilities that there could be one, two, three or four randomly selected persons who were vaccinated.
For only one person, we use P(1), same reasoning should hold for other subscripts.
P(1) = (61/100)(39/100)(39/100)(39/100) = 0.03618459
P(2) = (61/100)(61/100)(39/100)(39/100) = 0.05659641
P(3) = (61/100)(61/100)(61/100)(39/100) = 0.08852259
P(4) = (61/100)(61/100)(61/100)(61/100) = 0.13845841
Adding these probabilities, we have 0.319761. Therefore the probability of at least one person has been vaccinated out of 4 persons randomly selected is 0.32 or 32%, rounded off to the nearest hundredths.
