Question Completion:
How are the percentages distributed? Is the distribution skewed? Are there any gaps? (Select all that apply.)
Answer:
1. The percentages are concentrated from 20% to 60%.
2. These data are strongly skewed left.
3. There are no gaps in the data.
Step-by-step explanation:
1. Data
Percentage loss of wetlands per state
46 37 36 42 81 20 73 59 35 50
87 52 24 27 38 56 39 74 56 31
27 91 46 9 54 52 30 33 28 35
35 23 90 72 85 42 59 50 49
48 38 60 46 87 50 89 49 67
2. Re-arrangement of
Percentage loss of wetlands per state (in ascending order)
9 20 23 24 27 27 28 30
31 33 35 35 35 36 37 38
38 39 42 42 46 46 46 48
49 49 50 50 50 52 52 54
56 56 59 59 60 67 72 73
74 81 85 87 87 89 90 91
1) From the measure of 40°, you can write:
tan(40°) = 100/x, where x is the base from the building to the tower
⇒x=100/tan(40°) = 119,18 m
2) From the measure of 30°, you can write
tan(30°) = y / 119,18, where y is the height from the roof of Jill's building to the top of the tower.
Then, y = tan(30°) * 119,18 = 68,81 m
3) The height of Jill's building is 100 - 68,81 = 31,19 m
0.25 inches represents 1 mile
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Find 1 inch:
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1 inch represents 1 ÷ 0.25 miles
1 inch represents 4 miles
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Find 3.75 inches:
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1 inch represents 4 miles
3.75 inches represent 4 x 3.75 miles
3.75 inches represent 15 miles
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Find 2.25 inches:
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1 inch represents 4 miles
2.25 inches represent 4 x 2.25 miles
2.25 inches represent 9 miles
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Find Area:
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Area = Length x Width
Area = 15 x 9
Area = 135 miles²
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Answer: 135 miles²
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I think the answer would be 24 but im not 100% sure
We will use u-substitute:
Then for substitution:dx=u du. and integral becomes:
=u-ln(u+1)=
. Now we will change the values of limits:
=4-ln(5)-2+ln(3)=
2+ln(0,6)=2-0.51=1.49
