Question

In a recent questionnaire about food, a random sample of 970 adults were asked about whether they prefer eating fruits or vegetables, and 458 reported that they preferred eating vegetables. What value of z should be used to calculate a confidence interval with a 95 % confidence leve? Zo.10 Z0,05 Zo,025 20,01 Zo.005 1.960 1.282 2.326 2.576 1.645

Answer 1

Answer:

$Z_{0.05}=1.645$

Step-by-step explanation:

Given :In a recent questionnaire about food, a random sample of 970 adults were asked about whether they prefer eating fruits or vegetables, and 458 reported that they preferred eating vegetables.

To Find :What value of z should be used to calculate a confidence interval with a 95 % confidence level?

Solution:

Confidence level = 95 % i.e.0.95

So, significance level = 5% i.e. 0.05

So, the value of z corresponding to significance level 0.05 should be used  to calculate a confidence interval with a 95 % confidence level

So, $Z_{0.05}=1.645$

Hence z should be 1.645 to calculate a confidence interval with a 95 % confidence level.