2 years ago

A runner increases his velocity from 0 m/s to 20 m/s in 2.0s. What was his average acceleration?

Mathematics

1 answer:

xenn [34]2 years ago

7 0

change in velocity = 20 - 0 = 20

change in time = 2 seconds

Divide the change in velocity over the change in time: 20/2 = 10

The average acceleration is 10 m/s^2

I.e, each second, the speed increases by 10 m/s

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A seamstress has a piece of cloth that is 3 yards long. She cuts it into shorter lengths of 16 inches each. How many of the shor

harkovskaia [24]

She can cut 6 pieces. Here's how.
Three yards are 108 inches, 16 can go into 108, 6.75 times.

4 0

2 years ago

LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (-100,0) and (

Gre4nikov [31]

Answer:

$\frac {(x)^{2}}{8100}+\frac {(y)^{2}}{1900}=1$

Step-by-step explanation:

center of the hyperbola is (0,0) = (h, k)

c = the distance form the center to either focal point = 100

$c^{2} =100^{2}=10000$

The differences from the receiver to the transmitters = 2a

2a = 180 miles

a = 180/2=90 miles

$a^2 =90^{2}= 8100$

$b^{2}= c^{2} - a^{2}$

$b^{2}= 100^{2}-90^{2}=1900$

$b^{2}=1900$

The standard form is

$\frac {(x-h)^{2}}{a^{2}}+\frac {(y-k)^{2}}{b^{2}}=1$

$\frac {(x-0)^{2}}{a^{2}}+\frac {(y-0)^{2}}{b^{2}}=1$

$\frac {(x)^{2}}{8100}+\frac {(y)^{2}}{1900}=1$

3 0

2 years ago

Evaluate the function rule for the given value. y = 6 · 2^x for x = -2

strojnjashka [21]

Answer:

Step-by-step explanation:

To evaluate, substitute x= -2 into the equation $y = 6*2^x$ .

$y = 6*2^2\\y = 6*2^(-2)\\y = 6*\frac{1}{4}\\y = \frac{3}{2}$

8 0

2 years ago

What is the simplified form of the ninth root of x times the ninth root of x times the ninth root of x times the ninth root of x

Tomtit [17]

Let's convert the task into an example, simplifyng which will make us able to get the answer.
So, according to the task: $\sqrt[9]{x} * \sqrt[9]{x} * \sqrt[9]{x} * \sqrt[9]{x} 

= \sqrt[1/ 9 ]{x} * \sqrt[1/9]{x} * \sqrt[1/9]{x} * \sqrt[1/9]{x}$

Now we can simplify: $\sqrt[1/9]{x} + 1/9+1/9+1/9

= x^{4/9}$

So the answer is <span>C:x to the four ninths power</span>

6 0

2 years ago

Read 2 more answers

2.5 kg of cabbages cost £1.20<br><br> Work out the cost of 3.75 kg

s2008m [1.1K]

Thank you for your question!

In order to get the cost of 1 kg of cabbage, divide the cost by the quantity:

1.20/2.5
0.48

Now, multiply the amount for 1 kg to 3.75, because you need 3.75 times the amount.

0.48 * 3.75
1.80

So, it would cost 1.80 pounds for 3.75 kg.
Hope this helped!

8 0

2 years ago