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Viktor [21]
2 years ago
9

Solve the system of equations. 2.5y + 3x = 27 5x – 2.5y = 5 What equation is the result of adding the two equations? –8x = 328x

= 325y + 8x = 328x – 5y = 32 What is the solution to the system? (–4, 6)(–2.75, 8.6)(2.75, 3.5)(4, 6)

Mathematics
2 answers:
galben [10]2 years ago
4 0
A) The result of adding the two equations is
.. (2.5y +3x) +(5x -2.5y) = (27) +(5)
.. 8x = 32 . . . . . . . . . . . . . . . . . . . . . . . your 2nd selection

b) The solution to the system is (4, 6), your 4th selection.
.. This is the only choice with x=4, the solution to part (a).

nikitadnepr [17]2 years ago
3 0

Answer:

8x=32

(4,6)

Step-by-step explanation:

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Find the buoyant force of a rectangular solid of the given dimensions submerged in water so that the top side is parallel to the
11Alexandr11 [23.1K]

Answer:

Here is the continuation to the question ; The buoyant force is the difference between the fluid forces on the top and bottom of the solid. (The weight-density of water is 62.4 pounds per cubic foot.)

Hence, bouyant force is calculated as = 11980.8lb

Step-by-step explanation:

The steps are as shown in the attachment.

3 0
1 year ago
Approximately what is the length of the rope for the kite sail, in order to pull the ship at an angle of 45° and be at a vertica
Lera25 [3.4K]

Answer:

212m

Step-by-step explanation:

The set up will be equivalent to a right angled triangle where the height is the opposite side facing the 45° angle directly. The length of the rope will be the slant side which is the hypotenuse.

Using the SOH, CAH, TOA trigonometry identity to solve for the length of the rope;

Since we have the angle theta = 45° and opposite = 150m

According to SOH;

Sin theta = opposite/hypotenuse.

Sin45° = 150/hyp

hyp = 150/sin45°

hyp = 150/(1/√2)

hyp = 150×√2

hyp = 150√2 m

hyp = 212.13m

Hence the length of the rope for the kite sail, in order to pull the ship at an angle of 45° and be at a vertical height of 150 m is approximately 212m

8 0
1 year ago
Which equation is the inverse of y = 2x2 – 8?​
natita [175]

The inverse of the function is y=\pm \sqrt{\frac{x+8}{2}}

Explanation:

To find the inverse of the equation y=2x^{2} -8, we need to interchange the variables x and y for the variables y and x.

Thus, the equation becomes

x=2y^{2} -8

Now, we shall find the value of y.

Now, adding 8 to both sides of the equation, we have,

x+8=2y^{2}

Interchanging the sides,

2y^{2} =x+8

Dividing by 2 on both sides,

y^{2} =\frac{x+8}{2}

Taking square root on both sides,

y=\pm \sqrt{\frac{x+8}{2}}

Thus, the inverse of the function is y=\pm \sqrt{\frac{x+8}{2}}

5 0
2 years ago
A rectangle has height and width changing in such a way that the area remains constant 2 square feet. At the instant the height
hichkok12 [17]

Answer:

\frac{1}{3} ft/min is the rate of changing of width

Step-by-step explanation:

Given -

The area always remain constant i.2 2 square feet.

Height of the rectangle = 2 feet

Rate of changing of height = 6 feet per minute

Since area is constant

2 sq ft = (2 * 6) ft/min * 1 * x ft/min

x = \frac{1}{3} ft/min

4 0
1 year ago
Someone explain and help pls
jasenka [17]
Your answer for the girls in the gymnastics club is correct.

Do the percentage of water the same way:  Divide 139 by 197.
That'll give you the decimal amount that's covered by water.
To change the decimal to a percentage, move the decimal point
two places that way  ==> .
7 0
2 years ago
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