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svet-max [94.6K]
2 years ago
12

Which equation is the inverse of y = 2x2 – 8?​

Mathematics
1 answer:
natita [175]2 years ago
5 0

The inverse of the function is y=\pm \sqrt{\frac{x+8}{2}}

Explanation:

To find the inverse of the equation y=2x^{2} -8, we need to interchange the variables x and y for the variables y and x.

Thus, the equation becomes

x=2y^{2} -8

Now, we shall find the value of y.

Now, adding 8 to both sides of the equation, we have,

x+8=2y^{2}

Interchanging the sides,

2y^{2} =x+8

Dividing by 2 on both sides,

y^{2} =\frac{x+8}{2}

Taking square root on both sides,

y=\pm \sqrt{\frac{x+8}{2}}

Thus, the inverse of the function is y=\pm \sqrt{\frac{x+8}{2}}

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Arc CD is One-fourth of the circumference of a circle. What is the radian measure of the central angle?
Alex

Answer:

\frac{\pi }{2}

Step-by-step explanation:

Since the arc is \frac{1}{4} of the circumference, then

central angle = \frac{1}{4} × 2π ← angle in whole circle

central angle = \frac{2\pi }{4} = \frac{\pi }{2}

8 0
2 years ago
Hich expression is equivalent to -4(7 - 2m) + 11m?
Sholpan [36]

Answer:

- 4(7 - 2m) + 11m \\ =  - 28 + 8m + 11m \\ =   \boxed{19m - 28}

<em><u>Expression (19m-28) is equivalent to -4(7 - 2m) + 11m.</u></em>

3 0
1 year ago
A cement bridge post is 24 inches square and 15 feet 9 inches in length. If the cement weighs 145 pounds per cubic foot, how muc
lisov135 [29]

Answer:

The answer is option (C), One cement bridge post weighs 9,135 pounds

Step-by-step explanation:

Step 1: Get the total volume of a cement bridge post

The cement bridge post is in the shape of a cuboid, therefor the volume of the cement bridge post can be expressed as;

Volume of cement bridge post=Base area×Length

where;

Base area=(24^2) inches square

1 foot=12 inches

Convert 24 inches to foot=24/12=2^2=4 feet²

Length=15 feet and 9 inches

1 foot=12 inches

Convert 9 inches to foot=9/12=0.75 feet

Total length=(15+0.75)=15.75 feet

replacing;

Volume of cement bridge post=(4×15.75)=63 cubic feet

Volume of cement bridge post=63 cubic feet

Step 2: Get the total weight of the cement bridge post

Total weight of the cement bridge post=Weight per cubic foot×total volume of the cement bridge post

where;

Weight per cubic foot=145 pounds per cubic foot

Total volume of the cement bridge post=63 cubic feet

replacing;

Total weight of the cement bridge post=(145×63)=9,135 pounds

One cement bridge post weighs 9,135 pounds

8 0
1 year ago
What’s 8/15 divided by 4/5
iragen [17]

Answer: 2/3

Step-by-step explanation: In this problem, we have 8/15 ÷ 4/5. Dividing by a fraction is the same as multiplying by its reciprocal. In other words, we can change the division sign to multiplication and flip the second fraction.

8/15 ÷ 4/5 can be rewritten as 8/15 × 5/4

Now, we are simply multiplying fractions so we multiply across the numerators and multiply across the denominators.

8/15 × 5/4 = 40/60 = 2/3

8 0
2 years ago
Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A
MAVERICK [17]
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.

We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)

N = -(sin7A - sinA) + sin5A - sin3A
    = -2cos4A*sin3A + 2cos4A*sinA
    = 2cos4A(sinA - sin3A)
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    = -4cos4A*cos2A*sinA

D = cos7A + cosA - (cos5A + cos3A)
   = 2cos4A*cos3A - 2cos4A*cosA
   = 2cos4A(cos3A - cosA)
   = 2cos4A*(-2)sin2A*sinA
   = -4cos4A*sin2A*sinA

Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
       = cos2A/sin2A
      = cot2A

This verifies the identity.
4 0
1 year ago
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