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ycow [4]
2 years ago
7

Given the graphed function below, which of the following ordered pairs are found on the inverse function?

Mathematics
2 answers:
Dmitrij [34]2 years ago
4 0

Answer:

Its C (-9,-2)(-2,-1)(-1,0)(0,1)(7,2)

Step-by-step explanation:

fomenos2 years ago
4 0

Answer:

Step-by-step explanation:

Answer with explanation:

Suppose, y=√x ,is a polynomial function.Here Domain =[0,∞)

→ y²=x

Range =(-∞,∞)

To find the inverse of the given function,replace x by y, and y by x in the original function.

So, x=√y, is the equation of inverse function.

if a point (x,y) lies on original function, then point (y,x) lies on the inverse function.

The graphed function given below passes through points

(1,0),(0,-1),(-2,-9),(2,7),and (-1,-2).

So, inverse function of the above function will pass through

(0,1),(-1,0),(-9,-2),(7,2),and (-2,-1).

→→Option C

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Rob is making a scale model of the Solar System on the school field. He wants the distance from the Sun to Jupiter to be 8 metre
ANEK [815]

Answer:

1 : 9.75 * 10⁷

Step-by-step explanation:

To find n, we have to divide the real distance by the scale distance. This is 7.8 * 10⁸ / 8 = 0.975 * 10⁸ = 9.75 * 10⁷ which means that the ratio is 1 : 9.75 * 10⁷.

3 0
2 years ago
A cube-shaped water tank having 6 ft side lengths is being filled with water. The bottom is solid metal but the sides of the tan
Mekhanik [1.2K]

Answer:

0.033 ft

Step-by-step explanation:

Let g = 32.2 ft/s2 and h be the maximum height that water can be filled before the sides shatter.

Pressure is distributed from 0 to maximum at the bottom like the following equation:

P = \rho gh

So the force generated by water pressure on the side of the tank is

F = PA = \rho ghs/2

where s = 6ft is the side length of the tank. This force cannot be larger than 200lb

\rho ghs/2 \leq 200

62.4*32.2*h*6/2 \leq 200

h \leq 0.033 ft

4 0
2 years ago
Employees in the marketing department of a large regional restaurant chain are researching the amount of money that households i
kap26 [50]

Answer:

The <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.

Step-by-step explanation:

The data provided is as follows:

25 to 34              45 to 54

  1329                    2268

  1906                    1965

 2426                     1149

  1826                     1591

  1239                    1682

   1514                     1851

  1937                     1367

  1454                    2158

Compute the mean and standard deviation for the group "25 to 34" as follows:

\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [1329+1906+...+1454]=\frac{13631}{8}=1703.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1086710.875}=394.01

Compute the <em>z</em>-score for the group "25 to 34" as follows:

z=\frac{x-\bar x}{s}=\frac{1851-1703.875}{394.01}=0.3734\approx 0.37

Compute the mean and standard deviation for the group "45 to 54" as follows:

\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [2268+1965+...+2158]=\frac{14031}{8}=1753.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1028888.875}=383.39

Compute the <em>z</em>-score for the group "45 to 54" as follows:

z=\frac{x-\bar x}{s}=\frac{1851-1753.875}{383.39}=0.25333\approx 0.25

Thus, the <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.

8 0
2 years ago
Jenna earns $7.75 per hour working at the mall. If Jenna worked hours 22 1/5 last week, how much did she earn before taxes were
drek231 [11]
Jenna would earn gross pay of $172.05
7 0
2 years ago
What is the result of substituting for y in the bottom equation?
zhenek [66]

Answer:

(A)x + 3= x^2 + 2x-4

Step-by-step explanation:

Given the equations:

y = x + 3\\y= x^2 + 2x-4

Substitution simply means replacing the variable y in the second equation with its equivalent x+3 from the first equation.

Substitution of y into y=x^2 + 2x-4 gives us:

x + 3= x^2 + 2x-4

The correct option is A.

6 0
2 years ago
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