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Sav [38]
2 years ago
12

It takes 5 carpenters 5 hours to make 5 chairs. How long would it take 100 carpenters to make 100 chairs?

Mathematics
2 answers:
Elza [17]2 years ago
7 0
I hour because, one of the 5 carpenters built one chair in one hour, so one of the 100 carpenters would build one chair in one hour, there are only 95 more carpenters, nothing else different.
Hope I helped!
r-ruslan [8.4K]2 years ago
6 0
# of chairs = x
# of carpenters = y
Time = t

# of chairs (y) is directly proportional to tx
y = t * x

Therefore, y<span>1 * t1 / x1 = y2 * t2 / x2</span>
y1, t1, x1 = 5 and y2, x2 = 100 = > t2 = 5 

Answer: 5 minutes 
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The expression P(z&lt;1.00)= represents the area under the standard normal curve below a given value of z. Use your standard nor
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Answer:

The value of P(z<1.00)=0.8413

Step-by-step explanation:

Using a standard normal table, the area under the standard normal curve below the given value of z=1 is:

z         <u> .00</u>            .01

0.9   0.81594   0.81859

<u>1.0</u>    <u>0.84134</u>   0.84375

1.1     0.86433  0.86650


P(z<1.00)=0.84134

Rounded to 4 decimal paces

P(z<1.00)=0.8413


5 0
2 years ago
A school choir needs to make T-shirts for its 75 members and has set aside some money in their budget to pay for them. The membe
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50 + 3(B) + 50 + 3(R) + 50 + 3(Y) would be the equation.
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2 years ago
The image of a triangle after it has been dilated with a center of dilation at the origin has vertices at A prime(12, –6), B pri
nika2105 [10]

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5 0
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The area of the surface of the swimming pool is 210 square feet. what is the lenght d of the deep end (in feet)?
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3 0
2 years ago
Suppose that D(r) is a function which gives the population density, in hundreds of people per square mile, within r miles of the
borishaifa [10]

Answer:

a) T(r) = r.D(r)

b) 975 people per square mile.

Step-by-step explanation:

(a)

The units of D(r) are  

\frac{hundreds\;of\;people}{mile^2}

when multiplying the density by the area we get the amount of people in that area, so

T(r)=rmile^2D(r)\frac{hundreds\;of\;people}{mile^2}=rD(r)\;hundreds\;of\;people

(b)

The average rate of change of T(r) over the interval [5,7] is

\frac{T(7)-T(5)}{7-5}=\frac{7D(7)-5D(5)}{2}

but D(7) = 350 and D(5) = 100, so

\frac{7D(7)-5D(5)}{2}=\frac{7*350-5*100}{2}=975

and the average rate of change of T(r) over the interval [5,7] is 975 people per square mile.

5 0
2 years ago
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