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Andrew [12]
2 years ago
12

A system of equations is given below. y = negative 2 x + one-fourth and y = negative 2 x minus one-fourth Which of the following

statements best describes the two lines? They have the same slope but different y-intercepts, so they have no solution. They have the same slope but different y-intercepts, so they have one solution. They have different slopes but the same y-intercept, so they have no solution. They have different slopes but the same y-intercept, so they have one solution.
Mathematics
1 answer:
Ronch [10]2 years ago
9 0

Answer:

  They have the same slope but different y-intercepts, so they have no solution.

Step-by-step explanation:

The slope is the coefficient of x. In both cases, it is -2, so the lines have the same slope. (This eliminates the last two answer choices.)

The added constants are different for the two lines, so they have different y-intercepts. This means the lines are parallel and do not intersect.

A "solution" to the system of equations is a point (x, y) that satisfies both equations. Since the lines have no points in common, there are no solutions. (matches the first answer choice)

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Vesnalui [34]
<span>5200mL </span>→ 520 cL → 52dL →<span> 5.2L

</span><span>Example:

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Therefore:
<span>52L > 5200mL or 5.2L (True)


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The amount of rhubarb in the original recipe is 3 1/2 cups. Using what you know of whole numbers and what you know of fractions,
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The easiest way, I think, is to convert the mixed number into an improper fraction, then multiply by 3.
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A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w
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Answer:

(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412  

(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318  

And the 95% confidence interval would be given (-0.1412;-0.0318).  

We are confident at 95% that the difference between the two proportions is between -0.1412 \leq p_A -p_B \leq -0.0318

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p_A represent the real population proportion for business  

\hat p_A =\frac{75}{400}=0.1875 represent the estimated proportion for Business

n_A=400 is the sample size required for Business

p_B represent the real population proportion for non Business

\hat p_B =\frac{137}{500}=0.274 represent the estimated proportion for non Business

n_B=500 is the sample size required for non Business

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

And replacing into the confidence interval formula we got:  

(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412  

(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318  

And the 95% confidence interval would be given (-0.1412;-0.0318).  

We are confident at 95% that the difference between the two proportions is between -0.1412 \leq p_A -p_B \leq -0.0318

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