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2 years ago

13

The national electrical code allows a maximum voltage drop of 3% on branch circuits. What is the maximum allowable drop on a 240

-volt circuit

1 answer:

Andre45 [30]2 years ago

7 0

Answer:

7.2 volts

Step-by-step explanation:

3% of 240 is ...

0.03 × 240 = 3 × 2.40 = 7.20

The maximum allowable drop on a 240-volt circuit is 7.2 volts.

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Examine the steps used to solve the equation.

Elina [12.6K]

Answer:

see below

Step-by-step explanation:

12.5x − 10.2 = 3(2.5x + 4.2) - 6

Use the distributive property to distribute the 3

12.5x − 10.2 = 7.5x + 12.6 − 6

Combine like terms

12.5x − 10.2 = 7.5x + 6.6

Add 10.2 to each side of the equation by using the addition property of equality

12.5x = 7.5x + 16.8

Subtraction 7.5x from each side of the equation by using the subtraction property of equality

5x = 16.8

Divide by 5 on each side by using the division property of equality

x = 3.36

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Alberto is making a budget. He owes a cell phone bill of $60 per month for 23 more months, plus the fees for any extra usage suc

netineya [11]

I'm not sure what your book is saying about the matter but a cell phone is not usually an essential expense. If it is saying it is though, it would be an essential flexible expense.

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Round 2.1349 to the nearest hundredth. Explain in your own words why you round the number the way you do. Use a number line to s

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Answer:

2.13

Step-by-step explanation:

because 2.1349 is closer to 2.13 than 2.14 because the number 4 is less than 5 so it's closer to 0

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Factor completely. <br> 81x^2+180x+100

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(9x+10)² or (9x+10)(9x+10)

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2 years ago

In right triangle ABC, mC - 90° and AC BC. Which trigonometric ratio is cquivalent to sin b?

vaieri [72.5K]

Answer:

All trigonometric Ratios are $SinB = \frac{AC}{AB}$ , $SinA= \frac{CB}{AB}$ , $CosA= \frac{AC}{AB}$

And $Cos B = \frac{CB}{AB}$ .

Step-by-step explanation:

Given that,

A right angle triangle ΔABC, ∠C =90°.

Diagram of the given scenario shown below,

In triangle ΔABC :-

$Hypotenuse = AB\\Base = CB\\Perpendicular = AC$

So, $Sin\theta = \frac{perpendicular}{hypotenuse}$

$SinB = \frac{AC}{AB}$

Now, for ∠A the dimensions of trigonometric ratios will be changed.

Here the base for ∠A is AC , perpendicular side is CB and hypotenuse will be same for all ratios.

$SinA= \frac{CB}{AB}$

Again, $Cos\theta= \frac{base}{hypotenuse}$

Then, $CosA= \frac{AC}{AB}$

And $Cos B = \frac{CB}{AB}$ .

Hence,

All trigonometric Ratios are $SinB = \frac{AC}{AB}$ , $SinA= \frac{CB}{AB}$ , $CosA= \frac{AC}{AB}$

And $Cos B = \frac{CB}{AB}$ .

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2 years ago