Starting weight: 5/6 lb. Of this, Jan used 1/5, which would be (1/5)(5/6) lb,
or 1/6 lb, leaving 4/6 lb, or 2/3 lb. unused.
2/3 lb
Now divide 2/3 lb by 8 portions: ----------------- = (2/24) lb/portion, or
8 portions
1/12 lb/portion.
Answer:
Step-by-step explanation:
For the null hypothesis,
H0 : p = 0.63
For the alternative hypothesis,
Ha : p < 0.63
This is a left tailed test
Considering the population proportion, probability of success, p = 0.63
q = probability of failure = 1 - p
q = 1 - 0.63 = 0.37
Considering the sample,
Sample proportion, P = x/n
Where
x = number of success = 478
n = number of samples = 800
P = 478/800 = 0.6
We would determine the test statistic which is the z score
z = (P - p)/√pq/n
z = (0.6 - 0.63)/√(0.63 × 0.37)/800 = - 1.76
From the normal distribution table, the area below the test z score in the left tail 0.039
Thus
p = 0.039
X= 10
~because~
2x+5=8x, subtract 2x from both sides:
5=6x, divide 6 on both sides:
x=5/6, then rewrite the equation:
12(5/6)
x=10
