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2 years ago

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A pendant is formed using a cylinder and cone. Once assembled, as shown below, the pendant is painted. How many square millimete

rs are covered with paint? Express the answer in terms of π. 336π square millimeters 400π square millimeters 416π square millimeters 464π square millimeters

2 answers:

nadezda [96]2 years ago

6 0

Answer:

336π square millimeters on edge by the way props to the other guy who actually got it i want point i'm selfish

Step-by-step explanation:

d1i1m1o1n [39]2 years ago

3 0

Answer:

336π square millimeterz

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Two sides of an obtuse triangle measure 9 inches and 14 inches. The length of longest side is unknown. What is the smallest poss

julia-pushkina [17]

Answer:

17 inches

Step-by-step explanation:

An obtuse triangle is the triangle in which one of the side is the longest. It contains an obtuse angle and the longest side is the side that is opposite to the vertex of the obtuse angle.

Let the three sides of the obtuse triangle be a, b and c respectively with c as the longest side. Let a = 9 inches and b = 14 inches.

Now we know that for an obtuse triangle,

$c^2 > a^2 +b^2$

$c^2 > (9)^2 +(14)^2$

$c^2 > 81 +196$

$c^2 > 277$

c > 16.64

Therefore the smallest possible whole number is 17 inches.

4 0

1 year ago

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An urn contains 12 balls, five of which are red. Selection of a red ball is desired and is therefore considered to be a success.

SVEN [57.7K]

Answer:

2/10

Step-by-step explanation:

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2 years ago

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Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m

Dovator [93]

Option a: $\frac{m^{5} }{162n}$ is the equivalent expression.

Explanation:

The expression is $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ where $m\neq 0, n\neq 0$

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

$\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }$

Cancelling the like terms, we have,

$\frac{3^{-3}m^{5} n^{-1}}{6 }$

This equation can also be written as,

$\frac{m^{5}}{3^{3}6 n^{1} }$

Multiplying the terms in denominator, we have,

$\frac{m^{5} }{162n}$

Thus, the expression which is equivalent to $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ is $\frac{m^{5} }{162n}$

Hence, Option a is the correct answer.

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2 years ago

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How many possible values for y are there where y = cos^-1 0?

Arada [10]

Possible values for y are<u> infinite</u>

<h3>Further explanation </h3>

Trigonometry is the science of mathematics that studies the relationship between sides and angles in triangles

Given special angles of trigonometric functions, for example

$\displaystyle sin~0=0\\\\cos~30=\frac{1}{2}\sqrt{3}\\\\tan~45=1\\\\sec~45=\sqrt{2}\\\\etc.$

In the trigonometric function equation y = cos⁻¹ 0, then the value of y can be determined:

y = cos⁻¹0

y = arc cos 0

cos y = 0

Then the value of y :

$\displaystyle \frac{\pi }{2},\frac{3}{2}\pi,\frac{5}{2}\pi , etc$

Or can be formulated :

$\displaystyle y=\frac{\pi }{2} (2n-1)$ ⇒ y: arithmetic sequence

So there are infinite values for y

<h3>Learn more</h3>

trigonometric identities

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2 years ago

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Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by:

$z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811$

The confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

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2 years ago