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motikmotik
2 years ago
13

A ladder is leaning against a wall. The top of the ladder is 9 feet above the ground. If the bottom of the ladder is moved 3 fee

t farther from the wall, the ladder will be lying flat on the ground, still touching the wall. How long, in feet, is the ladder?

Mathematics
2 answers:
rjkz [21]2 years ago
8 0
So technically they are asking you to find the hypotenuse of a right angle triangle the height is 9ft and the length is 3ft so the formula is
A² +b²=c²

the a² and B² Being the height and length and label the third side c²

so..
9²+3²=c²
9×9+3×3=c²
81+9=c²
40=c²
√40=√c²
6.32=c
therefore the ladder is 6.32

well i think that is how you answer

murzikaleks [220]2 years ago
5 0
Check the picture below

\bf \textit{using the pythagorean theorem}\\\\
r^2=x^2+y^2\implies r=\sqrt{x^2+y^2}
\\\\\\
r=\sqrt{x^2+9^2}\implies r=\sqrt{x^2+81}\impliedby \textit{leaning ladder}
\\\\\\
r=\sqrt{(x+3)^2+0^2}\implies r=\sqrt{(x+3)^2}\impliedby \textit{flat ladder}\\\\
-------------------------------\\\\

\bf \sqrt{x^2+81}=\sqrt{(x+3)^2}\implies x^2+81=(x+3)^2
\\\\\\
x^2+81=x^2+6x+9\implies 81-9=6x\implies 72=6x\implies \cfrac{72}{6}=x
\\\\\\
\boxed{12=x}\\\\
-------------------------------\\\\
\textit{now, the ladder "r" is }\sqrt{(x+3)^2}\implies \sqrt{(12+3)^2}\implies 15

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We are asked to solve for the volume of the composite figures and the answer is the summation of the two volumes such as the volume of a triangular prism and volume of a rectangular prism. In order to solve this, we need to recall the following formulas:
the volume of triangular prism = 1/2* b*h*l  and solving the volume, we have it:
the volume of triangular prism = 1/2 * 15* 16*20 = 3600 units³
the volume of rectangular prism = l*w*h  and solving the volume, we have it:
the volume of rectangular prism = 20*15*12 = 2400 units³

The total volume of the composite figure is the summation of the two volumes such as:
total volume = 3600 + 2400
total volume = 6000 units²

The answer is 6,000 units².
5 0
2 years ago
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You just measured a sugar cube and obtained the following information: mass = 3.48 g height = length = width = 1.3 cm Determine
nignag [31]

Answer:     Volume of sugar cube=2.20 cm³

Density of sugar cube = 1.60 g/cm³.

The sugar cube will sink.

Step-by-step explanation:

Given : Mass of cube = 3.48 g

Also, dimension of sugar cube :

height = length = width = 1.3 cm

Since , the volume of cube = (side)³

Volume of sugar cube=(1.3) ³= 2.197 ≈ 2.20 cm³

Also, Density = \dfrac{\text{Mass}}{\text{Volume}}

⇒ Density of sugar cube = \dfrac{3.48}{2.2}=1.5818\approx1.60\ g/cm^3

∴ Density of sugar cube = 1.60 g/cm³.

It is known that the density of water is 1 g/cm³.

Here , density of sugar cube >  density of water

⇒ The sugar cube will sink .

5 0
2 years ago
9,290 is the value of the first 9 ten times as great as the value of the second 9?
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Answer:

No

Step-by-step explanation:

The first nine in on the place of the thousands, while the second nine is on the place of the tens. so the first nine is a hundred times as great as the second nine

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2 years ago
Perry, maria, and lorna are painting rooms in a college dormitory. working alone, perry can paint a standard room in 3 hours, ma
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Answer:Perry and Lorna take the maximum time and Maria and Lorna take the minimum time when they work together.

Explanation: Since, according to the question- Perry takes time when he works alone = 3 hours

Similarly, Maria takes = 2 hours, While Lorna takes= 2 hours 30 minutes or 2.5 hours.

since, there are three people thus their are three possibility to choose any two of them.

1- when Perry and Maria work together then time taken by them is \frac{1}{1/2+1/3}=\frac{1}{5/6}= 6/5= 1 hour 12 minutes.

2- when Maria and Lorna work together then time taken by them is \frac{1}{1/2 + 1/2.5}= 10/9= 1 hours 1/9 minutes ≈ 1 hours 7 min

3- when Perry and Lorna work together then time taken= \frac{1}{1/3+1/2.5}= 15/11= 1 hour 4/11 minutes≈ 1 hours 21 minutes

From the above explanation, it has been proved that when we talk about 2 members team then Perry and Lorna take the maximum time. While Maria and Lorna take the minimum time when they work together.


3 0
2 years ago
Read 2 more answers
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

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If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

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2 years ago
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