Answer:
0.0266, 0.9997,0.7856
Step-by-step explanation:
Given that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 points. Also suppose that IQs of students from university B can be described by a normal model with mean 120 and standard deviation 11. Let x be the score by A students and Y the score of B.
A)
B) Since X and Y are independent we have
X-Y is Normal with mean = 140-120 =20 and 

C) For a group of 3, average has std deviation = 

Answer:
B: Using x and y factor results in an expression of greater value than using x and y as terms.
Step-by-step explanation:
For her first expression, x and y are factors;
xy
For her second expression, x and y are written as terms;
x + y
For x and y are both negative integers, then;
-x * -y = xy ............... 1
-x + (-y) = - x - y
= - (x + y) .............. 2
Therefore, the value of x and y factors is greater than that when x and y are as terms. Thus the correct option is B.
Answer:
Step-by-step explanation:
Given is the probability distribution of a random variable X
X 4 5 6 7 Total
P 0.2 0.4 0.3 0.1 1
x*p 0.8 2 1.8 0.7 5.3
x^2*p 3.2 10 10.8 4.9 28.9
a) E(X) = Mean of X = sum of xp = 5.3

Std dev = square root of variance = 0.9
------------------------------------
b) For sample mean we have
Mean = 5.3
Variance = var(x)/n = 
c) 
Answer:
C i think not so sure bro gl tho
Step-by-step explanation: