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valentina_108 [34]
2 years ago
9

At the zoo, there are lions, tigers, bears, and monkeys. There are 2 lions. The number of lions and the number of tigers togethe

r equals the number of monkeys. There are 2 bears for every lion, and there are 3 tigers for every bear. What is the total number of lions, tigers, bears, and monkeys at the zoo?
Mathematics
2 answers:
horsena [70]2 years ago
7 0

Answer:

20

Step-by-step explanation:

2 lions with 6 tigers, 4 bears and 8 monkeys

garri49 [273]2 years ago
4 0

Answer:

so the answer is this

there is 2 lions right, and it tells us that for each lion there is two bears which makes it 4 bears in all and since we know that there is three tigers for every bear then that means that there is 12 tigers. And now since we know the number of tigers and the number of lions all we have to do to find the number of monkeys is add it up which makes it 14 monkeys. here is my work below

Step-by-step explanation:

lions-(1) -- (1) = (2 lions)

bears-(!!) -- (!!) = (4 bears)

tigers- (^^^) -- (^^^) -- (^^^) -- (^^^)= 12 tigers

monkeys- (%%%%%%%%%%%%%%) = 14 monkeys

Step-by-step explanation:

the total number of animals at that zoo is.

there are 32 animals in all that is including Monkeys, Lions, Tigers, and Bears

the total number of lions at the zoo is 2

the total number of tigers at the zoo is  12

the total number of bears at the zoo is 4

and the total number of monkeys at the zoo is 14

which makes it 32 animals in all at that zoo

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Answer:

He earned $114 in interest.

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Step-by-step explanation:

Initial balance (b): $760

Interest rate (i): 0.05

Period (n): 3 months

Simple interest applications yield the same amount in interest every period. Therefore, the total simple interest earned can be defined by:

I = n*B*i\\I= 3*760*0.05\\I=114

The final amount (A) in the account is the initial balance plus the interest earned in 3 months.

A = 760 +114\\A=874

He earned $114 in interest and the final amount in the account is $874

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2 years ago
Which number line represents the solution set for the inequality –negative StartFraction one-half EndFraction x is greater than
lozanna [386]

Answer:

<h2>Second choice.</h2>

Step-by-step explanation:

The given inequality is

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Let's solve for x

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Basically, the solution of the given inquality is set with all real numbers which are equal or less than -8. So, the solution must indicate a blue line starting at -8 pointing to its left.

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4 0
2 years ago
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What is the liability to equity ratio of chester? select: 1 2.84 1.61 .31 4.35?
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Answer:

1.61

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If f(x)=x2+10sinx, show that there is a number c such that f(c)=1000.
gayaneshka [121]
F(x) is continuous for all x.

Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.

At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.

Let's pick 40.
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Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
7 0
2 years ago
For the binomial expansion of (x + y)^10, the value of k in the term 210x 6y k is a) 6 b) 4 c) 5 d) 7
Sloan [31]

Answer:

a) 6

Step-by-step explanation:

Expanding the polynomial using the formula:

$(x+y)^n=\sum_{k=0}^n \binom{n}{k} x^{n-k} y^k $

Also

$\binom{n}{k}=\frac{n!}{(n-k)!k!}$

I think you mean 210x^6y^4

We can deduce that this term will be located somewhere in the middle. So I will calculate k= 5; k=6 \text{ and } k =7.

For k=5

$\binom{10}{5} (y)^{10-5} (x)^{5}=\frac{10!}{(10-5)! 5!}(y)^{5} (x)^{5}= \frac{10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5! }{5! \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 } \\ =\frac{30240}{120} =252 x^{5} y^{5}$

Note that we actually don't need to do all this process. There's no necessity to calculate the binomial, just x^{n-k} y^k

For k=6

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