Let the distance be d
Using pythagorean theorem,
d ≈ 119
The player ran for
119 meters
317 is the answer you are looking for.
Answer:
CIM
Step-by-step explanation:
C is the 3rd letter of the alphabet, A is the 1st, and B is the 2nd.
CAB = 3,1,2
Repeating for DEK:
DEK = 4,5,11
Comparing:
4−3 = 1
5−1 = 4
11−2 = 9
BED = 2,5,4, so adding the corresponding numbers:
2+1 = 3
5+4 = 9
4+9 = 13
So the code is CIM.
Answer:
a. 80 students
b. 92 students
Step-by-step explanation:
Represent arts students with A and Dance students with D.
So, we have,
n(A) = 35
n(D) = 57
Required
Determine n(A or D)
Solving (a):
Here, we have:
n(A and D) = 12
n(A or D) is calculated as thus:
n(A or D) = n(A) + n(D) - n(A and D)
n(A or D) = 35 + 57 - 12
n(A or D) = 80
b. From the given details
n(A and D) = 0 because both students are not mixed up as in (a) above
Using the same formula as (a).
n(A or D) = n(A) + n(D) - n(A and D)
n(A or D) = 35 + 57 - 0
n(A or D) = 92
