<h2>
Therefore he took 40 gram of
type solution and 10 gram of
type solution.</h2>
Step-by-step explanation:
Given that , A pharmacist 13% alcohol solution another 18% alcohol solution .
Let he took x gram solution of
type solution
and he took (50-x) gram of
type solution.
Total amount of alcohol =
gram
Total amount of solution = 50 gram
According to problem
⇔![\frac{ [x\times\frac{13}{100}] +[(50 -x) \times\frac{18}{100} ]}{50}= \frac{14}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Bx%5Ctimes%5Cfrac%7B13%7D%7B100%7D%5D%20%2B%5B%2850%20-x%29%20%5Ctimes%5Cfrac%7B18%7D%7B100%7D%20%5D%7D%7B50%7D%3D%20%5Cfrac%7B14%7D%7B100%7D)
⇔
⇔- 5x= 700 - 900
⇔5x = 200
⇔x = 40 gram
Therefore he took 40 gram of
type solution and (50 -40)gram = 10 gram of
type solution.
The maximum occurs when the derivative of the function is equal to zero.

Then evaluate the function for that time to find the maximum population.

Depending on the teacher, the "correct" answer will either be the exact decimal answer or the greatest integer of that value since you cannot have part of a rabbit.
The 3rd one is the answer