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Liono4ka [1.6K]

1 year ago

7

Let mAngleA = 40°. If AngleB is a complement of AngleA, and AngleC is a supplement of AngleB, find these measures. mAngleB = ° m

AngleC = °

2 answers:

kati45 [8]1 year ago

6 0

Answer:

B is 50° and C is 130°

Step-by-step explanation:

complementary angle

x+x=90°

40°+x=90°

x=90°-40°

x=50°

supplementary angles

x+x=180

50+x=180

x=180-50

x=30°

Ilia_Sergeevich [38]1 year ago

3 0

Answer:

m<B 50 m<C 130

Step-by-step explanation:

i jus did it :)

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The Hartman family is saving $400 monthly for Ronald's college education. The family anticipates they will need to

butalik [34]

Answer:

D. The family will likely have enough money. They will have saved $19,200 and have accumulated interest.

Step-by-step explanation:

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3 0

2 years ago

Write the first five terms of the geometric sequence in which a1=64 and the common ratio is 5/4

natita [175]

Remember that finding terms in a geometric sequence is done by multiplying the previous term by a common ratio $r$ . For example, we can say:

$a_2 = a_1 r$

$a_3 = a_2 r = (a_1 r)r = a_1 r^2$

We have $a_1 = 64$ . To find $a_2$ , let's multiply this term by $\frac{5}{4}$ :

$a_2 = 64 \cdot \frac{5}{4} = 80$

Now, let's use this to find all of our other terms:

$a_3 = 80 \cdot \frac{5}{4} = 100$

$a_4 = 100 \cdot \frac{5}{4} = 125$

$a_5 = 125 \cdot \frac{5}{4} = \frac{625}{4}$

Thus, our terms are 64, 80, 100, 125, and (625/4).

8 0

2 years ago

What is the solution of the system x − 3y = –13 and 5x + 7y = 34? A. `x = (6)/(5)`, y = 4 B. `x = (7)/(2), y = (9)/(2)` C. `x =

Masteriza [31]

For this case we have the following system of equations:

$x-3y = -13\\5x + 7y = 34$

From the first equation we clear "x":

$x = -13 + 3y$

We substitute in the second equation:

$5 (-13 + 3y) + 7y = 34$

We apply distributive property:

$-65 + 15y + 7y = 34$

We add similar terms:

$-65 + 22y = 34$

We add 65 to both sides:

$22y = 34 + 65\\22y = 99$

We divide between 22 on both sides:

$y = \frac {99} {22}\\y = \frac {9} {2}$

We look for the value of the variable "x":

$x = -13 + 3 \frac {9} {2}\\x = -13 + \frac {27} {2}\\x = \frac {-26 + 27} {2}\\x = \frac {1} {2}$

Thus, the solution of the system is:

$(x, y): (\frac {1} {2}, \frac {9} {2})$

ANswer:

$(x, y): (\frac {1} {2}, \frac {9} {2})$

5 0

2 years ago

Read 2 more answers

You have just finished paying off your $35,125 loan, a feat which took ten years of quarterly payments. The loan had an interest

mezya [45]

We have to compute first for the total cost of the loan by obtaining the monthly amortization:
<span> A= P/ [(1+ r/n)^n-1] /r(1+r/n)^n</span>
where
P= loan amount
P= $35125
r=interest rate of 7.44%
n = compounding frequency of 4
t= length of loan 10 years
A= $1252.7
Total cost = $1252.7x40=$50108
Computing the percentage of the finance charges
Finance charge = debt charge+service charge
Finance charge% =($50108-$32125+$5180.7)($50108+$5180.7)x 100
=36.47%
The answer is letter b.36.47%

3 0

1 year ago

Read 2 more answers

The number of pits in a corroded steel coupon follows a Poisson distribution with a mean of 6 pits per cm2. Let X represent the

Bas_tet [7]

Answer:

P(X=2)=0.0446

Step-by-step explanation:

If X follows a Poisson distribution, the probability p to have x pits in 1 cm2 is calculated as:

$p(x)=\frac{e^{-m}*m^x}{x!}$

Where m is the mean of pits per cm2, so, replacing m by 6 pits per cm2, we get that the probability is equal to:

$p(x)=\frac{e^{-6}*6^x}{x!}$

Now, the probability P(x=2) that there are 2 pits in a 1 cm2 is calculated as:

$p(x=2)=\frac{e^{-6}*6^2}{2!}\\p(x=2)=0.0446$

4 0

2 years ago