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kow [346]
1 year ago
11

Five friends have access to a chat room. Is it possible to determine who is chattingif the following information is known? Eithe

r Kevin or Heather, or both, are chatting. Either Randyor Vijay, but not both, are chatting. If Abby is chatting, so is Randy. Vijay and Kevin are either bothchatting or neither is. If Heather is chatting, then so are Abby and Kevin. Explain your reasoning
Mathematics
2 answers:
saw5 [17]1 year ago
8 0

Answer:

Most likely somebody using multiple accounts!

Step-by-step explanation:

If Heather is chatting, then so are Abby and Kevin. Isn't that suspicious or did they plan this?

If Abby is chatting, so is Randy. Vijay and Kevin Also Suspicious

fenix001 [56]1 year ago
4 0

Answer:

Kevin and Vijay are chatting

Step-by-step explanation:

Consider: Kevin=k

Heather=h

Randyor=v

Vijay=v

Abby=a

The values or the variables can be =o if they are not chatting and =1 if they arre chatting, then:

k+h>=1

v+r=1

a=r

v=k

if h=1 then a=1 and k=1, then as a=r, r=1 and as v=k, v=1, but then v+r=2, which is not possible because v+r=, then we can fisrt conclude than h=0.

.As k+h>=1, and h=0, then k=1. As k=v, then v=1.  

As v+r=1, and v=1, then r=0. As r=a, a=0

So in conclusion, a=0, r=0, v=1, k=1 and h=0, so Kevin and Vijay are chatting

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What are the roots of f(x) = x2 – 48?
notsponge [240]

Answer:

(x +sqrt(48)) (x-sqrt(48))

Step-by-step explanation:

sqrt = Square Root

sqrt(48) = 6.928

7 0
1 year ago
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The mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of
grandymaker [24]

Answer:

At the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.

Step-by-step explanation:

We are given that the mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of $2,000.

The ship building association wishes to find out whether their welders earn more or less than $20,000 annually.

<u><em>Let </em></u>\mu<u><em> = mean gross annual incomes of certified welders</em></u>

So, Null Hypothesis, H_0 : \mu = $20,000    

Alternate hypothesis, H_A : \mu \neq $20,000

Here, null hypothesis states that the mean income of welders is equal to $20,000.

On the other hand, alternate hypothesis states that the mean income of welders is not $20,000.

Also, the test statistics that would be used here is <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                              T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean income

            \sigma = population standard deviation = $2,000

            n = sample size

Now, at the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.

3 0
2 years ago
In 2001, a total of 15,555 homicide deaths occurred among males and 4,753 homicide deaths occurred among females. The estimated
deff fn [24]

Answer:

a. 11

b. 3

c. homicide mortality rate

d. 11:3

Step-by-step explanation:

a.) If 15,555 homicide cases were recorded among males of 139,813,000 population, then in every 100,000 males, the number of homicides cases will become:

= [15,555/139,813,000] * 100,000

= 11.13 aproximately 11 homicide cases in every 100,000 males.

b.) If 4,753 homicide cases were recorded among Females of 144,984,000 population, then in every 100,000 Females, the number of homicides cases will become:

= [4753/144,984,000] * 100,000

= 3.28 approximately 3 homicide cases in every 100,000 females

C.) Homicide-mortality rate

d.) ratio of male to female homicide rate = 11 : 3

e.) What those rates means is that in every 100,000

Males in 2001, 11 of them were Victims of homicide and in every 100,000 females, 3 of them are victims of homicide.

6 0
2 years ago
Your band is one of 8 bands competing at the battle of the bands. The order of the performances is determined at random. The fir
lorasvet [3.4K]

Answer:

1.79 %.

Step-by-step explanation:

you have to calculate the probability of a series of events before you can calculate the final probability.

The first event is that the band plays on Friday.

If there are 8 bands, but only 5 play on Friday, then the probability that they will play on Friday is

5/8

Now, the second event that they are the last ones is 1/5, since they are 5 bands.

Therefore the probability that they will play on Saturday and last is

5/8 * 1/5 = 1/8

Now, for the rival band it would be, knowing that on Friday there is already a quota assigned and one band less, the probability that they will play that day is

4/7

as they play before the other group, it would be 1/4, as there is already a quota assigned.

The final probability would then be:

4/7 * 1/4 = 1/7

Now the probability that the band gives the last performance on Friday night and your rival band performs immediately before them, is:

1/8 * 1/7 = 0.0179

That is 1.79 %.

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2 years ago
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2 years ago
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