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2 years ago

What is the completely factored form 8x2-50y2?

Mathematics

1 answer:

lorasvet [3.4K]2 years ago

7 0

Remember
a²-b²=(a-b)(a+b)

8x²-50y²
2(4x²-25y²)
(2)([2x]²-[5y]²)
2(2x-5y)(2x+5y)

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How can Ari simplify the following expression? StartFraction 5 Over a minus 3 EndFraction minus 4 divided by 2 + StartFraction 1

Zielflug [23.3K]

Answer:

$-\frac{8}{3}$

Step-by-step explanation:

Given

$\frac{5}{-3} - \frac{4}{2} + \frac{1}{-3}$

Required

Simpify

The very first step is to take LCM of the given expression

$\frac{-10 -4 - 2}{6}$

Perform arithmetic operations o the numerator

$-\frac{16}{6}$

Divide the numerator and denominator by 2

$-\frac{16/2}{6/2}$

$-\frac{8}{3}$

The expression can't be further simplified;

Hence, $\frac{5}{-3} - \frac{4}{2} + \frac{1}{-3}$ = $-\frac{8}{3}$

8 0

2 years ago

A rice merchant purchased 50 bags of rice at rupees 300 per back he spent 500 rupees towards transportation due to lack of deman

Alex777 [14]

Answer:

10500 rupees

Step-by-step explanation:

So 50 bags 300 per pack so

300*50= 15000

15000 is what he spent on the 50 bags of rice

So he spent 500 rupees on transportation

15000 + 500 = 15500 total spent which is not needed but extra information

30% loss is 30% of 15000 so

30% of 15000 = 4500

15000 - 4500 = 10500 rupees

8 0

2 years ago

Find the missing value to the nearest hundredth cos _____ 7/18

Bezzdna [24]

I believe D will be the correct answer.

6 0

2 years ago

A mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt. Th

Arturiano [62]

Answer:

The probability of hitting the bullseye at least once in 6 attempts is 0.469.

Step-by-step explanation:

It is given that a mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt.

The probability of hitting bullseye in each attempt, p = 0.10

The probability of not hitting bullseye in each attempt, q = 1-p = 1-0.10 = 0.90

Let x be the event of hitting the bullseye.

We need to find the probability of hitting the bullseye at least once in 6 attempts.

$P(x\geq 1)=1-P(x=0)$ .... (1)

According to binomial expression

$P(x=r)=^nC_rp^rq^{n-r}$

where, n is total attempts, r is number of outcomes, p is probability of success and q is probability of failure.

The probability that the dart thrower not hits the bullseye in 6 attempts is

$P(x=0)=^6C_0(0.10)^0(0.90)^{6-0}$

$P(x=0)=0.531441$

Substitute the value of P(x=0) in (1).

$P(x\geq 1)=1-0.531441$

$P(x\geq 1)=0.468559$

$P(x\geq 1)\approx 0.469$

Therefore the probability of hitting the bullseye at least once in 6 attempts is 0.469.

3 0

2 years ago

What values of b satisfy 4(3b + 2)2 = 64?

Vikentia [17]

Given the equation 4(3b + 2)² = 64, dividing both sides of the equation by 4, we have (3b + 2)² = 16 and getting the square root of both sides, (3b + 2) = 4 and (3b + 2) = -4 We can solve for b for each equation and have 3b = 2 | 3b = -6 b = 2/3 | b = -2 Therefore, the values of b are 2/3 and -2 and from the choices, the answer is <span>A: b = 2/3 and b = -2.</span>

8 0

1 year ago