Let
x-----------------> books in <span>the first shelf
</span>y-----------------> books in the second shelf
z-----------------> books in the third shelf
we know that
x+y+z=158-------------> equation (1)
x=y-8---------> y=x+8 -------> equation (2)
x=z+5--------> z=x-5 --------> equation (3)
<span>
substitute (2) and (3) in (1)
</span>x+(x+8)+(x-5)=158--------> 3x=155----------> x=51.7
<span>the number of books in the first shelf (x=51.7) is not a whole number
therefore
the answer is
Is not possible to place the amount of 158 books in the amounts indicated in the problem</span>
This is the concept of sinusoidal, to solve the question we proceed as follows;
Using the formula;
g(t)=offset+A*sin[(2πt)/T+Delay]
From sinusoidal theory, the time from trough to crest is normally half the period of the wave form. Such that T=2.5
The pick magnitude is given by:
Trough-Crest=
2.1-1.5=0.6 m
amplitude=1/2(Trough-Crest)
=1/2*0.6
=0.3
The offset to the center of the circle is 0.3+1.5=1.8
Since the delay is at -π/2 the wave will start at the trough at [time,t=0]
substituting the above in our formula we get:
g(t)=1.8+(0.3)sin[(2*π*t)/2.5]-π/2]
g(t)=1.8+0.3sin[(0.8πt)/T-π/2]
Answer:
James's monthly income is $1250.
Step-by-step explanation:
If the budget accounts for James's entire monthly income, the sum of the cost of all the items on the budget is his total monthly income.
Income = 300 + 175 + 125 + 200 + 250 + 50 + 25 + 125 = $1250
D + 3n = 1 Subtract d from both sides
3n = 1 - d Divide both sides by 3
n = 
Answer:
Longest possible length for each of the shorter lengths of ribbon is 9 cm because greatest common factor for both 36 and 45 is 9.
Step-by-step explanation:
Alannah has two ribbons one length is 36cm and other is 45cm.
It asked to find shorter length of ribbons that each cut into equal pieces with out no ribbon left over.
So, let's find greatest common factor for both 36 and 45.
Let's prime factor each number
36= 2*2*3*3
45= 3*3*5
So, GCF is product of common factors for both numbers.
GCF= 3*3 =9
So, longest possible length for each of the shorter lengths of ribbon is 9 cm.
Learn more about GCF in brainly.com/question/21612147.
