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GarryVolchara [31]
2 years ago
13

An animal shelter needs to find homes for 40 dogs and 60 cats. If 15% of the dogs are female, and 25% of the cats are female, wh

at percent of the animals are female?
Someone please answer.... I really need this

I will give brainliest. PLEASE HELP!!!
Mathematics
1 answer:
Harrizon [31]2 years ago
3 0

Answer:

21% of the animals are female

Step-by-step explanation:

In total:

There are 40 + 60 = 100 animals.

Female animals.

40 dogs. Of those, 15% are female. So 0.15*40 = 6.

60 cats. Of those, 25% are female. So 0.25*60 = 15.

21 female animals.

21/100 = 0.21 = 21%

21% of the animals are female

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A: a horizontal shrink would be caused by cos 3x.
B: a vertical stretch would be caused by 3 cos x
C:  a horizontal stretch would be caused by cos (1/3)x
D: a vertical shrink would be caused by 1/3 cos x.
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1 year ago
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I need to find both of the solutions to the equation 100+(n-2)^ = 149
rodikova [14]

Answer:

Step-by-step explanation:

hello :

100+(n-2)² = 149

100-100+(n-2)² = 149-100

(n-2)² = 49  

(n-2)² - 49  =0    but 49=7²

(n-2)² - 7²  =0   use identity : a²-b²=(a-b)(a+b)

(n-2-7)(n-2+7)=0

(n-9)(n+5)=0

n-9=0 or n+5=0

n=9 or n=-5

                                             

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2 years ago
Maddy is carrying a 555 liter jug of sports drink that weighs 7.5\text{ kg}7.5 kg7, point, 5, start text, space, k, g, end text.
Lelu [443]

Answer:

w/2 = 7.5/5

3kg

Step-by-step explanation:

Remaining question below:

Which proportion could Maddy use to model this situation?

a. w/2 = 7.5/5

b. w/7.5 = 5/2

Solve the proportion to determine the weight of a 2 liter jug.

_____kg

5 liters jug of sport drink weighs 7.5kg

2 liters jug of sport drink will weigh x kg

Find w

Ratio of weight to volume

7.5kg : 5liters=7.5/5

wkg : 2 liters=w/2

Equates the ratio

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6 0
1 year ago
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The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Eddi Din [679]

Answer:

Step-by-step explanation:

Hello!

You have the math and writing SAT scores of twelve students.

There are two variables of interest X₁: Math SAT score of a student. and X₂: Writing the SAT score of a student.

These two variables aren't independent since both of them represent data corresponding to the same student, meaning, that the math and writing scores belong to the same students and not to two separate groups of students.

This is an example of paired samples, to make the statistical test you have to establish a third variable, this variable will be the difference between the other two:

Xd= X₁-X₂

Xd: "Difference between the Math and Writing SAT scores of a student.

This variable has a normal distribution Xd~N(μd;σd²)

a. Using a .05 level of significance and test for a difference between the population mean for the math scores and the population mean for the writing scores? Enter negative values as negative numbers. Round your answer to two decimal places.

The parameter of interest is μd is the population mean of the difference between the math and writing SAT scores of the students.

The hypotheses are:

H₀: μd=0

H₁: μd≠0

α: 0.05

The test statistic is a t-student for dependent samples and it's rejection region is two-tailed.

t= \frac{Xd[bar]-Mud}{Sd/\sqrt{n} } = \frac{25-0}{37.05/\sqrt{12} } = 2.33

What is the p-value? Round your answer to four decimal places.

The p-value for this test is: 0.0394

The p-value is less than the level of significance, the decision is to reject the null hypothesis.

b. What is the point estimate of the difference between the mean scores for the two tests?

The sample mean for the variable "difference" is X[bar]d

You can calculate the point estimate of the sample mean of the variable Xd using two ways.

1) You calculate all the differences between the pairs of scores, add them and divide them by the sample size

X[bar]d= ∑di/n

∑di= 300

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X[bar]d= 300/12= 25

2) You can calculate the sample mean for each variable and then calculate the difference between the two sample means

X[bar]₁= ∑X₁/n

∑X₁= 6168

X[bar]₁= 6168/12= 514

X[bar]₂= ∑X₂/n

∑X₂= 5868

X[bar]₂= 5868/12= 489

X[bar]d= X[bar]₁-X[bar]₂ = 514 - 489= 25

What are the estimates of the population mean scores for the two tests?

Math test X[bar]₁= 514

Writing test X[bar]₂= 489

Which test reports the higher mean score?

The Math test reports a higher mean score.

I hope it helps!

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Arturiano [62]
Hi there.

Using process of elimination & some logic, I believe the answer is:

C) starting size of the pumpkin

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1 year ago
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