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uranmaximum [27]
2 years ago
15

Janie ordered boxed lunches for a student advisory committee meeting. Each lunch costs $4.25. The total cost of the lunches is $

53.75, including a $7 delivery fee.
Mathematics
2 answers:
andriy [413]2 years ago
7 0

Answer:

11 boxed lunches

Step-by-step explanation:

Full question

Janie ordered boxed lunches for a student advisory committee meeting. Each lunch cost 4.25. The total cost of the lunches is 53.75, including a 7$ delivery fee. Write and solve an equation to find x the number of boxed lunches Janie ordered

First of all subtract the delivery feesince it was inckuded in the total cost, this will now be the total cost of all the noxed lunches ordered by Janie, then divide the balance of the total cost by the cost of one boxed lunch to get thd total boxed kunches

X= 53.75-7/4.25

X= 53.75-7= 46.75/4.25

X=11

Shkiper50 [21]2 years ago
7 0

Answer:

The total number of lunch boxes is 11.

<em>⇒ 4.25x + 7 = 53.75 (equation)</em>

<u>Step-by-step explanation:</u>

If 1 lunch box costs $ 4.25

x lunch boxes costs x × 4.25 = 4.25x

Janie paid a total of $ 53.75 including delivery

<em>⇒ 4.25x + 7 = 53.75 (equation)</em>

4.25x = 53.75 - 7

4.25x = 46.75

∴x = \frac{46.75}{4.25} = 11

<u>Therefore, Janie bought 11 boxes.</u>

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Answer:

a). x = 11

b). m∠DMC = 39°

c). m∠MAD = 66°

d). m∠ADM = 36°

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Step-by-step explanation:

a). In the figure attached,

m∠AMC = 3x + 6

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Therefore, MC is the angle bisector of angle AMD.

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                   = 88 - 49

                   = 39°

c). m∠MAD = 2(m∠DAC)

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d). Since, m∠AMD + m∠ADM + m∠MAD = 180°

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e). m∠ADC = \frac{1}{2}(m\angle ADM)

                   = \frac{1}{2}(36)

                   = 18°

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1 year ago
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