It is given in the question that
The temperature measured in Kelvin (K) is the temperature measured in Celsius (C) increased by 273.15. This can be modeled by the equation

To solve for C, we need to get rid of 273.15 and for that we do subtraction, that is

Correct option is the first option .
Given
Elysse paid for her sandwich and drink with a $10 bill and received $0.63 in change.
The sandwich cost $7.75 and sales tax was $0.47.
Find out the cost of her drink
To proof
Let the cost of her drink be x.
As given in the question
Elysse paid for her sandwich and drink with a $10 bill and received $0.63 in change.
Elysse paid for her sandwich and drink = 10 - 0.63
= $ 9.37
sandwich cost $7.75 and sales tax was $0.47
Than the equation becomes
x = 9.37 - (7.75 + 0.47)
x = 9.37 - 8.22
x = $ 1.15
The cost of the drink is $ 1.15.
Hence proved
we know that

The company charges
cents per kilowatt-hour of electricity
Step
Find the cost for the light bulb
a) in one day


Cost=$
b) In a year



Cost=$
Step
Find the cost for the led bulb
a) in one day


Cost=$
b) In a year



Cost=$
Step
Find the difference in cost
therefore
the answer is

Please consider the attached graph.
We have been given that Ben is eating some pretzels and an entire small package of mustard as a snack. We are asked to find the equation that represents the relationship between the number of pretzels that Ben eats, x, and the total amount of sodium in his snack, y.
First of all, we will find the slope of the line using points (1,80) and (5,140).



Now we will use point-slope form of equation
, where m represents slope of line and point
is on the line.
We will substitute
and coordinates of point (1,80) in above equation.



Therefore, the equation
represents the relationship between the number of pretzels that Ben eats and the total amount of sodium in his snack.
Answer:
Which graph is the result of reflecting f(x) = One-fourth(8)x across the y-axis and then across the x-axis?
On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and incresaes into quadrant 1. It goes through the y-axis at (0, 0.25) and goes through (1, 2).
On a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases in quadrant 2. It crosses the y-axis at (0, 0.25) and goes through (negative 1, 2).
On a coordinate plane, an exponential function approaches y = 0 in quadrant 3 and decreases into quadrant 4. It crosses the y-axis at (0, negative 0.25) and goes through (1, negative 2).
On a coordinate plane, an exponential funtion increases in quadrant 3 into quadrant 4 and approaches y = 0. It goes through (negative 1, negative 2) and crosses the y-axis at (0, negative 0.25).
Step-by-step explanation: