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Ghella [55]
2 years ago
7

Of the total number of people on a cruise ship, 1/4 or child passengers. 2/5 of the remaining people were crew. There were 1320

crew on board how many adult passengers were there
Mathematics
1 answer:
Nuetrik [128]2 years ago
5 0
<h2>462</h2>

Step-by-step explanation:

       Total number of people on the cruise ship was 1320.

\frac{1}{4}^{th} of the people were child passengers. Number of child passengers = \dfrac{1}{4}\times (\text{Total number of people})=\dfrac{1}{4}\times 1320=330

\frac{2}{5}^{th} of the people were crew. Number of people that were crew = \dfrac{2}{5}\times (\text{Total number of people})=\dfrac{2}{5}\times 1320=528

       Remaining people in the ship constitute the adult passengers.

       Number of adult passengers = (\textbf{Total number of people})-(\textbf{Total number of children})-(\textbf{Total number of crew})=1320-330-528=\textbf{462}

∴ Number of adult passengers = 462

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Maria started her business with $50 in her bank account. At the end of the month, she had +$60 in her account in addition to the
Sladkaya [172]
In the original statement, it says 'in addition to the initial $50' meaning that you're adding $50+$60. The correct answer would be: She gained $60.
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1 year ago
Question Number 12 You are a landscaper working on the design of a parking lot in a new shopping center. You are measuring the l
vovikov84 [41]

Answer:

Length\: of\: D=37\frac{3}{16}  \:feet

Step-by-step explanation:

The following are the given information:

  • The handicapped spot, which is 10\frac{1}{16} feet wide and next to the curb.
  • The other three spots are 8\frac{3}{8} feet wide.
  • There are 4 dividing lines between the spots, and each measures \frac{1}{2} foot.

The Median D therefore will be a sum of the following:

  • The width of the Handicapped Spot
  • 3 X The width of the other spots
  • 4 X The width of the dividing line

= 10\frac{1}{16} + (3 X 8\frac{3}{8})+(4 X\frac{1}{2})\\=\frac{161}{16} +  \frac{3 X 67}{8}+\frac{4}{2}\\=\frac{161}{16} +  \frac{201}{8}+\frac{4}{2}\\=\frac{161+402+32}{16}\\=\frac{595}{16}\\Length\: of\: D=37\frac{3}{16}  \:feet

7 0
2 years ago
Greenfields is a mail order seed and plant business. The size of orders is uniformly distributed over the interval from $25 to $
LekaFEV [45]

Answer:

a) 47.55

b) 58

c) 47.88

Step-by-step explanation:

Given that the size of the orders is uniformly distributed over the interval

$25 ( a ) to $80 ( b )

<u>a) Determine the value for the first order size generated based on 0.41</u>

parameter for normal distribution is given as ;  a = 25,  b = 80

size/value of order  = a + random number ( b - a )

                                = 25 + 0.41 ( 80 - 25 )

                                =  47.55

<u>b) Value of the last order generated based on random number (0.6)</u>

= a + random number ( b - a )

= 25 + 0.6 ( 80 - 25 )

= 25 + 33 = 58

<u>c) Average order size </u>

= ∑ order 1 + order 2 + ----- + order 10  ) / 10

= (47.55 + ...... + 58 ) / 10

= 478.8 / 10 = 47.88

4 0
2 years ago
Find the general form of the function that satisfies da/dt = -9a
posledela
The given equation is
\frac{da}{dt} =-9a

This ODE (Ordinary Differential Equation) is separable.
That is,
\frac{da}{a} = -9

Integrate to obtain
\int  \frac{da}{a} =-9 \int dt \\\\ ln(a) = -9t + k \\\\ a(t) = c \, e^{-9t}
where k, c are constants.

Answer:  a(t) = c \, e^{-9t}, c = constant.

4 0
1 year ago
Read 2 more answers
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