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padilas [110]
1 year ago
6

A survey of 100 people found that 35 people exercise in the morning, 45 people exercise in the afternoon, and 20 people exercise

at night. Tara claims that 35:55, 45:80, and 20:65 are possible ratios from this data. Jim claims that 35:100, 45:100, and 20:100 are possible ratios from this data. Who is correct? Explain.​
Mathematics
2 answers:
Rashid [163]1 year ago
7 0

100 total people ... 35 exercise in the morning ... 45 in the afternoon ... and 20 at night

Jim is correct ...

35/100 is the ratio of people who exercise in the morning to total people.

45/100 is the ratio of afternoon exercisers to total people

20/100 is the ratio of night exercisers to total people

Vadim26 [7]1 year ago
5 0

Answer: Jim is correct because 35:100, 45:100, and 20:100 are part-to-whole comparisons. There are other possible part-to-part ratios from the data.

Step-by-step explanation: sample response

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Julie gathered data about the numbers of pages and chapters in several books by her favorite author.The equation of the line of
erica [24]

Answer:

C

Step-by-step explanation:

To get the approximate number of pages in the chapters, what we need to do is to substitute for the value of x in the line of best fit equation.

Thus, we have;

y = 15.261(8) + 8.83 = 122.088 + 8.83 = 130.918

This is approximately equal to 131

7 0
2 years ago
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a square painting has an area of 81x^2-90x-25. A second square painting has an area of 25x^2+30x+9. What is an expression that r
galina1969 [7]

Answer:

The answer in the procedure

Step-by-step explanation:

Let

A1 ------> the area of the first square painting

A2 ---->  the area of the second square painting

D -----> the difference of the areas

we have

A1=81x^{2}-90x-25

A2=25x^{2}+30x+9

case 1) The area of the second square painting is greater than the area of the first square painting

The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting

D=A2-A1

D=(25x^{2}+30x+9)-(81x^{2}-90x-25)

D=(-56x^{2}+120x+34)

case 2) The area of the first square painting is greater than the area of the second square painting

The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting

D=A1-A2

D=(81x^{2}-90x-25)-(25x^{2}+30x+9)

D=(56x^{2}-120x-34)

4 0
2 years ago
Brock is training for a Crossfit competition. He began the training completing pull-ups and box jumps origanally, his training p
siniylev [52]

If the adjusted ratio was 2:7, then

2x is the number of pull-ups

and

7x is the number of box jumps.

You can state that since he completed 63 box jumps at the end of his training, then

7x=63,

x=9

and

2x=18.

The total number of exercises performed is 2x+9x=18+63=81.

As at start the ratio was 5:4, then

5y was the number of pull-ups

and

4y was the number of box jumps.

Therefore, 5y+4y=81,

9y=81,

y=9

and 5y=45, 4y=36.

Answer: Initially: 45 pull-ups and 36 box jumps. At the end: 18 pull-ups and 63 box jumps.

8 0
2 years ago
Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni
viktelen [127]

Answer:

the answer is C

Step-by-step explanation:

using her first part 2 kilometers in 18 minutes

total kilometers - 2

and total time - 18

so you would get:

k – 2 = (t – 18)

4 0
1 year ago
Find the general solution of y''' + 6y'' + y' − 34y = 0 if it is known that y1 = e−4x cos(x) is one solution.
SashulF [63]

Answer:

Step-by-step explanation:

Given is a differential equation of III order,

y''' + 6y'' + y' - 34y = 0

The characteristic equation would be cubic as

m^3+6m^2+m-34=0

By trial and error, we find that

f(2) = 2^3+6(2^2)+2-34 =0\\

Thus m=2 is one solution

Since given that e^{-4x} cos xis one solution we get

m = -4+i and hence other root is conjugate m=-4-i

Hence general solution would be

y=Ae^{2x} +e^{-4x} (Bcosx +C sinx)

3 0
2 years ago
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