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solong [7]
2 years ago
5

What is the value of minus 6 x cubed minus y squared minus 3 x y if if x = -2 and y = 4

Mathematics
2 answers:
Oksi-84 [34.3K]2 years ago
8 0

Well, "minus 6 x cubed minus y squared minus 3 x y" translates to:

-6x^{2} -y^{2} -3xy

Then, if we insert the values for x and y, we get:

-6(-2)^{2} -(4)^{2} -3(-2)(4)

When we distribute and multiply:

144-16-24

And once we combine like terms:

104<em> is the answer</em>


Kaylis [27]2 years ago
8 0

The given statement can be written in expression form as

-6x^3-y^2-3xy

As the value of x=-2 and y=4 are given .

To find the value of expression at the given values of x and y , we have to insert the values into the expression

-6(-2)^3-(4)^2-3(-2)(4)

Now solving by cubing and squaring the numbers

-6(-8)-16-3(-8)

As negative negative is positive and positive negative is negative

48-16+24

Adding like terms and subtracting we get

72-16=56

56 is the Answer

Hope this will help

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Jim's work evaluating 2 (three-fifths) cubed is shown below. 2 (three-fifths) cubed = 2 (StartFraction 3 cubed Over 5 EndFractio
Blizzard [7]

Answer:

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3}) and not 2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5})

Step-by-step explanation:

Jim's work evaluating 2(\frac{3}{5}) ^{3} is shown:

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5})=2(\frac{3X3X3}{5})=2(\frac{27}{5})=\frac{54}{5}

If you look at the Second step, the exponent is taken over only the numerator. It should have been taken over both the numerator and denominator as shown below.

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3})

The correct workings therefore is:

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3})=2(\frac{3X3X3}{5X5X5})=2(\frac{27}{125})=\frac{54}{125}

7 0
2 years ago
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A consumer is considering two different purchasing options for the car of their choice. The first option, which is leasing, is d
AVprozaik [17]

Answer:

  • y=250x+4000
  • y=400x+400

Step-by-step explanation:

Given that:

  • x represents the number of months of ownership; and
  • y represents the total paid for the car after ‘x' months.

<u>First Option (Leasing)</u>

250x - y + 4000 = 0

Expressing the equation in the Slope-Intercept Form y=mx+b, we have:

y=250x+4000

<u>Second Option (Financing)</u>

$400 for 0 months of ownership, (0,400), and $4400 for 10 months of ownership, (10, 4400).

First, we determine the slope of the line joining (0,400) and (10,4400)

Slope, m= \dfrac{4400-400}{10-0}= \dfrac{4000}{10}=400

We have:

y=400x+b

When y=400, x=0

400=400(0)+b

b=400

Therefore, the Slope-Intercept Form of the second option is:

y=400x+400

<u>Significance</u>

  • In the first option, there is a down payment of $4000 and a monthly payment of $250.
  • In the second option, there is a down payment of $400 and a monthly payment of $400.

<u>Part B</u>

We notice from the graph that after 24 months, the cost for leasing and financing becomes the same ($10,000). Therefore, a consumer will be better off financing since the downpayment for leasing is higher.

<u>i.e </u>

  • When x=0, y=$4000 for leasing
  • When x=0, y=$400 for financing

4 0
2 years ago
M.C. Escher was a famous artist who used unique viewpoints in his drawings that moved beyond flat plane surfaces. In his drawing
Alenkinab [10]
<span>hyperbolic geometry was what he used</span>
6 0
1 year ago
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Marco has drawn a line to represent the perpendicular cross-section of the triangular prism. Is he correct? Explain. triangular
evablogger [386]

Answer:

The correct option is;

Yes, the line should be perpendicular to one of the rectangular faces

Step-by-step explanation:

The given information are;

A triangular prism lying on a rectangular base and a line drawn along the slant height

A perpendicular bisector should therefore be perpendicular with reference to the base of the triangular prism such that the cross section will be congruent to the triangular faces

Therefore Marco is correct and the correct option is yes, the line should be perpendicular to one of the rectangular faces (the face the prism is lying on).

8 0
1 year ago
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A hyperbola centered at the origin has a vertex at (0, 36) and a focus at (0, 39).
likoan [24]
To solve this problem you must apply the proccedure shown below:
 1. You have that the hyperbola <span>has a vertex at (0,36) and a focus at (0,39).
 2. Therefore, the equation of the directrices is:

 a=36
 a^2=1296
 c=39

 y=a^2/c

 3. When you susbtitute the values of a^2 and c into </span>y=a^2/c, you obtain:
<span>
 </span>y=a^2/c
<span> y=1296/13

 4. When you simplify:

 y=432/13

 Therefore, the answer is: </span><span>y = ±432/13</span>
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2 years ago
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