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Simora [160]
1 year ago
8

Given ΔADC and ΔAEB, What is AE?

Mathematics
1 answer:
chubhunter [2.5K]1 year ago
4 0

Answer:

AE = 43.2 units

Step-by-step explanation:

As per the given question image, it can be seen that in the \triangle ADC \text { and }\triangle AEB :

1. \angle B = \angle C = 90^\circ

2. \angle A is common to both the triangles.

3. Two angles are common, so the third angle \angle E is also equal to \angle D.

All the three angles in the \triangle ADC \text { and }\triangle AEB are equal to each other, hence the triangles are similar.

As per the property of similar triangles, the ratio of their sides will be equal.

AB : AC = AE : AD

AC = 88 units

BC = 55 units

AB = AC - AB = 33 units

Let side AE = x units

Side AD = AE + ED

So, AD = x + 72

Using the ratio:

\dfrac{AB}{AC} = \dfrac{AE}{AD}\\\Rightarrow \dfrac{33}{55} = \dfrac{x}{x+72}\\\Rightarrow 55x = 33 \times 72\\\Rightarrow x = \dfrac{3\times 72}{5}\\\Rightarrow x = 43.2\ units

So, AE = 43.2 units

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Consider the trinomial 9x2 + 21x + 10. What value is placed on top of the X? What value is placed on the bottom of the X? What i
inna [77]

Answer: 1) Value is placed on top of the X =90

2) Value is placed on the bottom of the X =21

3)  Factored form will be (3x+5)(3x+2)

Step-by-step explanation:

Since we have given that

9x^2 + 21x + 10

As we know the quadratic form :

ax^2+bx+c=0

1) Value is placed on top of the X is given by

a\times c=9\times 10=90

2) Value is placed on the bottom of the X is given by

b=21

3) Factorised form:

We will use "Split the middle term":

9x^2 + 21x + 10\\\\=9x^2+15x+6x+10\\\\=3x(3x+5)+2(3x+5)\\\\=(3x+2)(3x+5)

Hence, Factored form will be

(3x+5)(3x+2)

7 0
2 years ago
Read 2 more answers
Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours of production time
user100 [1]

The question is incomplete, here is the complete question

Recall the production model from Section 1.3:

Max 10x

s.t. 5x ≤ 40

x ≥ 0

Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours for each unit produced. Assume total production capacity remains 40 units. Use y as the number of units of product 2 produced. . Show the mathematical model when both products are considered simultaneously.

Answer:

Max Profit: 10x + 5y

5x + 2y ≤ 40

x ≥ 0, y ≥ 0

Explanation:

x= number of units of product 1 produced

y = number of units of product 2 produced

Since the first product, x, has a unit profit of $10 and Max1 is 10x

Second product, y, has a unit profit of $5, Max2 = 5y

The maximum profit when both products are considered simultaneously is 10x + 5y

Max Profit = 10x + 5y

Time required for each unit of x is 5hours

Therefore, time required for x units is 5x hours

Time required for each unit of y is 2hours  

Therefore, time required for y units is 2y hours

Time required for the simultaneous production of both products is 5x + 2y

Since production capacity remains 40 units, 5x+2y ≤40

NB: The values of x and y cannot be negative  

5 0
1 year ago
Employees in the marketing department of a large regional restaurant chain are researching the amount of money that households i
kap26 [50]

Answer:

The <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.

Step-by-step explanation:

The data provided is as follows:

25 to 34              45 to 54

  1329                    2268

  1906                    1965

 2426                     1149

  1826                     1591

  1239                    1682

   1514                     1851

  1937                     1367

  1454                    2158

Compute the mean and standard deviation for the group "25 to 34" as follows:

\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [1329+1906+...+1454]=\frac{13631}{8}=1703.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1086710.875}=394.01

Compute the <em>z</em>-score for the group "25 to 34" as follows:

z=\frac{x-\bar x}{s}=\frac{1851-1703.875}{394.01}=0.3734\approx 0.37

Compute the mean and standard deviation for the group "45 to 54" as follows:

\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [2268+1965+...+2158]=\frac{14031}{8}=1753.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1028888.875}=383.39

Compute the <em>z</em>-score for the group "45 to 54" as follows:

z=\frac{x-\bar x}{s}=\frac{1851-1753.875}{383.39}=0.25333\approx 0.25

Thus, the <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.

8 0
1 year ago
3) George walks away from his house. He walks 25 km west and then
Romashka-Z-Leto [24]

Answer:

29.15 km

Step-by-step explanation:

Given;

George walks; 25km west and then 15 km south

Resolving the directions to x and y axis;

North and South represent positive and negative y axis.

East and West represent positive and negative x axis respectively.

25km west

Rx = -25 km

15 km south

Ry = -15 km

The resultant displacement from the house is;

R = √(Rx^2 + Ry^2)

Substituting the values;

R = √((-15)^2 + (-25)^2)

R = √(225+625)

R = √(850)

R = 29.15 km

Therefore, he is 29.15 km from house

8 0
1 year ago
three positive numbers are in Arithmetic Progression (A.P). the sum of the squares of the three numbers is 155. while the sum of
Alecsey [184]
Given:
Three numbers in an AP, all positive.
Sum is 21.
Sum of squares is 155.
Common difference is positive.

We do not know what x and y stand for.  Will just solve for the three numbers in the AP.
Let m=middle number, then since sum=21, m=21/3=7
Let d=common difference.
Sum of squares
(7-d)^2+7^2+(7+d)^2=155
Expand left-hand side
3*7^2-2d^2=155
d^2=(155-147)/2=4
d=+2 or -2
=+2  (common difference is positive)

Therefore the three numbers of the AP are
{7-2,7,7+2}, or
{5,7,9}


6 0
2 years ago
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