Answer:
<em>Find the probability of success in a single trial and then think about the nature of the problem (when do we stop). </em>
Step-by-step explanation:
Observe that in the single trial, we have (8 4) possibilities of choosing our set of balls. If we have chosen two white balls and two black balls, the probability of doing that is simply
p=(4 2)*(4 2)/(8 4)
This is well know Hyper geometric distribution. Now, define random variable X that marks the number of trials that have been needed to obtain the right combination (two white and two black balls). From the nature of the problem, observe that X has Geometric distribution with parameter p that has been calculated above. Hence
P(X = n) = (1— p)^n-1 *( p )
<em>Find the probability of success in a single trial and then think about the nature of the problem (when do we stop). </em>
Answer:
.98
Step-by-step explanation:
1-(35/43)^18 im in stats too tehee
Answer:
12 trades
Step-by-step explanation:
Let's call 'x' the number of trades they will do.
After each trade, the number of cards Ian has increase by 1 (he gives 1 but receives 2), and the number of cards Jason has decrease by 1 (he receives 1 but gives 2), so after x trades, the number of cards Ian has is 20 + x, and Jason has 44 - x.
To find the number of trades when they will have the same amount of cards, we have that:
20 + x = 44 - x
2x = 24
x = 12 trades
