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2 years ago

ernesto tiene que enviar 4 encomiendas que tienen una masa del total de ocho decimos de kg. ¿que fraccion de kg. tiene cada una

1 answer:

Ber [7]2 years ago

6 0

⭐Solución de problemas: Cada encomiendo tiene un peso de 2 kilogramos. En fracción esto representa 1/4 de la masa total.

¿por qué? Usted tiene una masa total entre los 4 encomiendos de 8 kilogramos, por lo que en orden

para expresar el peso de cada uno de ellos, tenemos

la siguiente expresión: Masa total de encomiendas (kg)/Número de encomiendas (unidad)Sustituimos:

8 kg/4 s

2 kg por encomiendaOfertamos la fracción que representa cada una en el total:

kg por encomienda/total de kg

2/8 x 1/4

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6 questions = 30 points someone please help me

eduard

Answer:

1)D

2)D

3)A

4)B

5)Cannot Answer - No data

6)C

7)C

6 Questions answered for 30 points.

Step-by-step explanation:

Answer for the 1st Question,

Area of a cylinder can be calculated by,

Area of the cylindrical part = $2\pi rL$

Area of the parts that cover the open parts of cylinder = $2\pi r^2$

Therefor Total are of the cylinder = $2\pi rL+2\pi r^2$

Area of the total cylinder = $2*3.14*6.8*14.2+2*3.14*6.8^2$

= $896.784$

Therefor best estimate will be D) 923 in^2

Answer for the 2nd Question,

ABC is a triangle.

By Pythagorean theorem it says,

$(AC)^2+(CB)^2=(AB)^2$

The distance from A to C = 6

The distance from C to B = 5

$(AC)^2=6^2=36$

$(CB)^2=5^2=25$

$(AC)^2+(CB)^2=(AB)^2=36+25=61$

Therefor $(AB)^2=61\\(AB)=\sqrt{61}$

Therefor Answer is D) Sqr 61

Answer to Question 3

To find the trend you can draw an imaginary line that fits the scatter plots.(I have attached a image drawing the imaginary lines)

Then the revenue can be calculated by calculating the area covered by the imaginary line drawn or area "under" the curve.

Area of the Store 1 = $\frac{1}{2} *(110+40)*110=8250$

Area of the Store 2= $\frac{1}{2} *110*80=4400$

Therefore Revenue from Store 1 = $8250

Revenue from Store 2 = $4400

Answer is A) Store 1 has more sales revenue

Answer for Question 4

$\frac{5}{12}=0.4167\\\frac{5}{11}=0.4545$

You can straight away discard answer D because it is less than both 5/12 and 5/11.

Also you can discard Answer C because 25/264 is very small (less than 1/10=0.1)

$\frac{11}{23} =0.4782$ , therefor this is not in between those two numbers.

Then it has to be $\frac{115}{264} =0.4356$

Answer is B)

Answer for question 6

The equation of a straight line is of the form $y=mx+c$

here m is the gradient and c is the intercept.

Find the intercept(c) by finding the y value when x value is 0, here it is +1.

Gradient (m) of the graph can be found by,

$\frac{y1-y2}{x1-x2} =\frac{7-3}{3-1} =2$

Therefor the equation of the graph is,

$y=2x+1$

Answer is C

Answer for question 7

$\frac{7}{8} =0.875$

$\frac{6}{9} =0.67$

We can discard answer A because the value is close to 0.5

We can discard answer B because 3/17 is a very small value (0.17)

$\frac{53}{72} =0.73$ , This falls between the above 2 numbers.

Therefor answer is C

5 0

2 years ago

a car travels 30 1/2 miles in 2/3 of an hour. what is the average speed, in miles per hour, of the car ?

Contact [7]

Answer:

speed=225.75 miles per hour

Step-by-step explanation:

given:

s=301/2

t=2/3

we have,

v=s/t

v=(301/2)/(2/3)

=(301/2)×3/2

=903/4

v=225.75

therefore, speed of car will be 225.75 miles per hour

6 0

1 year ago

Which statements correctly describe the cosine and sine functions? Check all that apply. The cosine function increases on (90°,

Jet001 [13]

Answer:

The three correct answers are B "The sine function increases on (0°, 90°) and (270°, 360°)." , E "Both the cosine and sine functions have a maximum value of 1.", and F "Both the cosine and sine functions are periodic."

Step-by-step explanation:

Hope this helps <3

4 0

2 years ago

What's the unit rate 975 revolutions in 3 mins

cricket20 [7]

Answer:

325 rpm's

Step-by-step explanation:

975 revolutions in 3 minutes

divide 975 by 3 to get the number of revolutions per minute (rpm)

3 0

2 years ago

The base b(t)b(t)b, (, t, )of a triangle is decreasing at a rate of 131313 millimeters per minute and the height h(t)h(t)h, (, t

dem82 [27]

Answer:

8.5 square mm per minute

Step-by-step explanation:

A = 1/2bh

A' = (1/2)(b'h +bh') . . . . differentiating with respect to time

A' = (1/2)((-13)(1) +(5)(6)) = (1/2)(17) = 8.5 . . . . mm²/min

The area is increasing at the rate of 8.5 mm²/min.

_____

Numerical solution

Consider the triangle dimensions .01 minutes before and after the time of interest.

before: base = 5 + 0.13 = 5.13 mm; height = 1 - 0.06 = 0.94 mm. area = 2.4111 mm²

after: base = 5 -0.13 = 4.87 mm; height = 1 +.06 = 1.06 mm. area = 2.5811 mm²

Average rate of change in that period is

(2.5811 -2.4111)/0.02 = .17/.02 = 8.5 . . . . mm²/min

_____

Comment on the numbers

Note that we have assumed the base is decreasing at 13 mm/min. Quite often, division bars get lost on Brainly, so we're not sure this isn't 1/3 mm/min. At the assumed rate, the triangle will disappear in 5/13 minutes, about 23.08 seconds, when the base becomes zero. Of course, it only came into existence 1/6 minute (10 seconds) ago, when the height became non-zero.

3 0

2 years ago