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katrin [286]
2 years ago
9

ernesto tiene que enviar 4 encomiendas que tienen una masa del total de ocho decimos de kg. ¿que fraccion de kg. tiene cada una

Mathematics
1 answer:
Ber [7]2 years ago
6 0

⭐Solución de problemas: Cada encomiendo tiene un peso de 2 kilogramos. En fracción esto representa 1/4 de la masa total.

Y

¿por qué? Usted tiene una masa total entre los 4 encomiendos de 8 kilogramos, por lo que en orden

para expresar el peso de cada uno de ellos, tenemos

la siguiente expresión: Masa total de encomiendas (kg)/Número de encomiendas (unidad)Sustituimos:

8 kg/4 s

2 kg por encomiendaOfertamos la fracción que representa cada una en el total:

kg por encomienda/total de kg

2/8 x 1/4

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Ann is grouping 38 rocks. She can put them into groups of 10 rocks or as single rocks. What are the different ways Ann can group
hoa [83]

Answer: There will be two different ways of doing so.

Step-by-step explanation:

Since we have given that

Total number of rocks =38

If we want to groups of 10 rocks or as single rocks then there are 2 different ways ;

<u>Case I:</u>

if we group into 10 rocks

there will be four sets in which Ist set contains 10 rocks

Second set contains 10 rocks

Third set contains 10 rocks

and Fourth set remains with 8 rocks only.

<u>Case II:</u>

if we group as single rocks .

There will be 38 sets .



7 0
2 years ago
The area of a second soup can’s base is 5 pi inches squared. The can has a height of 10 inches. How would you use that informati
Ilia_Sergeevich [38]

Answer:

The amount of soup the can will hold is;

50π inches cubed = 157.08 inches cubed

Step-by-step explanation:

The amount of soup the can will hold is equal to the volume of the can.

Volume of the can = base area × height

Given;

Base Area = 5π inches squared

height = 10 inches

Volume of can = 5π × 10 = 50π inches cubed

The amount of soup the can will hold is;

50π inches cubed = 157.08 inches cubed

8 0
2 years ago
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The table below represents the closing prices of stock ABC for the last 5 days. What is the r-value of the linear regression tha
pentagon [3]
To answer this one, you may use scientific calculator that is capable of generating the value of r in the regression. We let the day be the values of x and the value be the values of y. By performing the task in the scientific calculator, it was found out that the value of r is -0.947.
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You have a fishing line spool with an end that has an area of 20.0 cm2. How much fishing line do you need to wind around the spo
lana66690 [7]
<h3>Problem Solution</h3>

Assuming the spool is a cylinder and the circumference we're winding around is that of a circle with the given area, we can write the relation between circumference and area as

... C = 2√(πA)

10 times the circumference is then

... 10C = 20√(π·20 cm²) = 40√(5π) cm ≈ 159 cm

<h3>Formula Derivation</h3>

The usual formulas for circumference and area are

... C = 2πr

... A = πr²

If we multiply the area formula by π and take the square root, we get

... πA = (πr)²

... √(πA) = πr

Multiplying this by 2 gives circumference.

... C = 2√(πA) = 2πr

3 0
2 years ago
Elyria Warehousing desired to locate a central warehouse to serve five Ohio markets. Placed on a grid system, its five markets h
Iteru [2.4K]

Answer:

The correct option is 2.

Step-by-step explanation:

According to the the center-of-gravity technique, the coordinates of the center-of-gravity location are

(\frac{\sum x_iL_i}{\sum L_i},\frac{\sum y_iL_i}{\sum L_i})

Where ((x_i,y_i) represent the coordinates and L_i is demand.

We have to find the Y-coordinate of the center-of-gravity location.

The sum of product of demand and corresponding y coordinates is

\sum y_iL_i=65\times 2200+55\times 900+95\times 1300+200\times 1750+175\times 3100=1208500

The sum of demanded units is

\sum L_i=2200+900+1300+1750+3100=9250

The Y-coordinate of the center-of-gravity location is

y_0=\frac{\sum y_iL_i}{\sum L_i}

y_0=\frac{1208500}{9250}

y_0=130.6486

y_0\approx 131

The Y-coordinate of the center-of-gravity location is 131. Therefore the correct option is 2.

7 0
2 years ago
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