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DochEvi [55]
1 year ago
9

Burn is to ointment as grief is to

Mathematics
1 answer:
Nitella [24]1 year ago
4 0

Answer:The answer is Sympathy

Step-by-step explanation:

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If you were to plot y versus m using the equation y = (g/k) m yo, how would you calculate the value for k?
Zanzabum

Equation is given as;

y = (g/k) yo

To find the value of “k”, divide both sides of the equation with yo;

y/yo = (g/k)yo/yo

it implies that;

y/yo = (g/k)

Now following steps will obtain the value of “k” as;

ky/yo = g

ky = gyo

<span>k = gy0/y </span>

3 0
2 years ago
Withdrawing $10 every week from an outstanding balance of $400
den301095 [7]
-10w - 400 = o

w= weeks
o = new outstanding balance
8 0
2 years ago
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A control chart is developed to monitor the analysis of iron levels in human blood. The lines on the control chart were obtained
sergejj [24]

Answer:

Step-by-step explanation:

Hello!

The variable is X: iron level on human blood.

It has a mean of μ= 51.50 mg/dl and a standard deviation of σ= 3.50 mg/dl.

According to the control chart, the process should be shut down for troubleshooting when the analysis shows values X[bar]≥ 53.42 mg/dl and X[bar]≤ 49.58 mg/dl

Warnings are received at levels X[bar]≥52.78 mg/dl and X[bar]≤ 50.22 mg/dl

The system works between levels 49.58<X[bar]<53.42 and works without warnings between 50.22<X[bar]<52.78.

Using these parameters you have to analyze if the lists of sample means to see which ones are within the working values are wich ones are outside this interval.

<u>Sample 1</u>

Min= 50.15

Max= 51.99

Mean= 51.61

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>This sample's min value is below the lower limit of the warning interval but not low enough to reach action levels, the max value is within the working range.</em>

<em><u /></em>

<u>Sample 2 </u>

Min= 50.32

Max= 52.56

Mean= 51.16

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both the max and min values of the sample are within the working range without warning.</em>

<em />

<u>Sample 3</u>

Min= 50.25

Max= 53.12

Mean= 51.83

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>The max value of this sample is above the upper limit of the warning interval but does not surpass the upper bond of the troubleshoot interval. Min value is within working values.</em>

<em />

<u>Sample 4</u>

Min= 50.05

Max= 53.01

Mean= 51.70

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values surpass the warning interval but do not reach action levels</em>.

<u>Sample 5</u>

Min= 50.35

Max= 52.71

Mean= 51.37

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values are within working levels without warnings.</em>

<em />

Considering that samples reaching warning levels should be shut down as a precaution, they are classified as:

Shutdown: Sample 1, 3 and 4

Do not shutdown: Sample 2 and 5.

I hope it helps!

8 0
2 years ago
Kira looked through online census information to determine the average number of people living in the homes in her city. What is
Goshia [24]
First we need to identify if the data is qualitative or quantitative.

The data is average number of people living in the homes.

Qualitative data as its name indicates is an attribute or characteristic. It can not be measured e.g color. Quantitative data is such a data which can be counted or measured.

Since the average number of people can be counted and measured, the data is Quantitative.

In an observational study the individuals are observed. In the given case, Kira did not observed the individuals to gather the data, rather she used an Online resource to gather the data.

Therefore, the correct answer will be:
Kira used published data that is quantitative.
4 0
2 years ago
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if owen has a collection of nickels and quarters worth $8.10. if the nickles were quarters and the quarters were nickels, the va
sp2606 [1]
We can model this situation as a system of linear equation, where n is the number of nickels and q is the number of quarters.

\left \{ {{0.05n + 0.25q=8.10} \atop {0.25n+0.05q=17.70}} \right.

Solving the system of equations,  there are 67 nickels and 19 quarters.
8 0
2 years ago
Read 2 more answers
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