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2 years ago

Emma's sister is nine years older than Emma. Their combined ages add up to 49.How old is Emma. write and equation and solve

2 answers:

5 0

E= Emma's age
emma's sister's age= e+9 (emma's age plus 9)

e+9=49
(isolate your variable)
e+9-9=49-9
e=40
Emma is 40 years old
To check: Emma's sister is 9 years older right? take emmas age 40 plus the nine more years and you still get the total of 49! hope that helps good luck

german2 years ago

5 0

Answer:

E= Emma's age

emma's sister's age= e+9 (emma's age plus 9)

e+9=49

(isolate your variable)

e+9-9=49-9

e=40

Emma is 40 years old

To check: Emma's sister is 9 years older right? take emmas age 40 plus the nine more years and you still get the total of 49! hope that helps good luck

hehe

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A flight of stairs is supported by two columns, as shown in the diagram.

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Answer:

12 feet

Step-by-step explanation:

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2 years ago

A candy maker produces mints that have a label weight of 20.4 grams. Assume that the distribution of the weights of these mints

Sliva [168]

Answer:

a)0.099834

b) 0

Step-by-step explanation:

To solve for this question we would be using , z.score formula.

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

A candy maker produces mints that have a label weight of 20.4 grams. Assume that the distribution of the weights of these mints is normal with mean 21.37 and variance 0.16.

a) Find the probability that the weight of a single mint selected at random from the production line is less than 20.857 grams.

Standard Deviation = √variance

= √0.16 = 0.4

Standard deviation = 0.4

Mean = 21.37

x = 20.857

z = (x-μ)/σ

z = 20.857 - 21.37/0.4

z = -1.2825

P-value from Z-Table:

P(x<20.857) = 0.099834

b) During a shift, a sample of 100 mints is selected at random and weighed. Approximate the probability that in the selected sample there are at most 5 mints that weigh less than 20.857 grams.

z score formula used = (x-μ)/σ/√n

x = 20.857

Standard deviation = 0.4

Mean = 21.37

n = 100

z = 20.857 - 21.37/0.4/√100

= 20.857 - 21.37/ 0.4/10

= 20.857 - 21.37/ 0.04

= -12.825

P-value from Z-Table:

P(x<20.857) = 0

c) Find the approximate probability that the sample mean of the 100 mints selected is greater than 21.31 and less than 21.39.

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1 year ago

Keith has 40-pound bags of mulch in his truck that weigh a total of 3600 pounds. His Owner’s Manual lists the truck’s capacity a

kiruha [24]

Answer:

Keith must remove 90-75 = 15 bags in order to meet the weight requirements

Step-by-step explanation:

This problem can be solved by consecutive rules of three problem.

Rule of three problem:

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.

In this problem, the measures are:

- The number of bags

- The total weight

As the number of bags increases, so do the total weight. So, the relationship between the measures is direct.

To know how many bags does Keith need to remove in order to meet the weight requirements, we first need to know how many bags are in the truck currently.

The problem states that each bag weighs 40 pounds and the weight of the truck is 3600 pounds, so:

1 bag - 40 pounds

x bags - 3600 pounds

40x = 3600

$x = \frac{3600}{40}$