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2 years ago

Emma's sister is nine years older than Emma. Their combined ages add up to 49.How old is Emma. write and equation and solve

2 answers:

5 0

E= Emma's age
emma's sister's age= e+9 (emma's age plus 9)

e+9=49
(isolate your variable)
e+9-9=49-9
e=40
Emma is 40 years old
To check: Emma's sister is 9 years older right? take emmas age 40 plus the nine more years and you still get the total of 49! hope that helps good luck

german2 years ago

5 0

Answer:

E= Emma's age

emma's sister's age= e+9 (emma's age plus 9)

e+9=49

(isolate your variable)

e+9-9=49-9

e=40

Emma is 40 years old

To check: Emma's sister is 9 years older right? take emmas age 40 plus the nine more years and you still get the total of 49! hope that helps good luck

hehe

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A water trough has two congruent isosceles trapezoids as ends and two congruent rectangles as sides.

BlackZzzverrR [31]

Answer:

Part a) The exterior surface area is equal to $160\ ft^{2}$

Part b) The volume is equal to $240\ ft^{3}$

Part c) The volume water left in the trough will be $84\ ft^{3}$

Step-by-step explanation:

Part a) we know that

The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles

Find the area of two rectangles

$A=2[12*5]=120\ ft^{2}$

Find the area of two trapezoids

$A=2[\frac{1}{2}(8+2)h]$

Applying Pythagoras theorem calculate the height h

$h^{2}=5^{2}-3^{2}$

$h^{2}=16$

$h=4\ ft$

substitute the value of h to find the area

$A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}$

The exterior surface area is equal to

$120\ ft^{2}+40\ ft^{2}=160\ ft^{2}$

Part b) Find the volume

We know that

The volume is equal to

$V=BL$

where

B is the area of the trapezoidal face

L is the length of the trough

we have

$B=20\ ft^{2}$

$L=12\ ft$

substitute

$V=20(12)=240\ ft^{3}$

Part c)

step 1

Calculate the area of the trapezoid for h=2 ft (the half)

the length of the midsegment of the trapezoid is (8+2)/2=5 ft

$A=\frac{1}{2}(5+2)(2)=7\ ft^{2}$

step 2

Find the volume

The volume is equal to

$V=BL$

where

B is the area of the trapezoidal face

L is the length of the trough

we have

$B=7\ ft^{2}$

$L=12\ ft$

substitute

$V=7(12)=84\ ft^{3}$

4 0

2 years ago

Given: EFGH inscribed in k(O) m∠FHE = 45°, m∠EGH = 49° Find: m∠FEH

hodyreva [135]

Answer:

$m$

Step-by-step explanation:

we know that

The inscribed angle measures half that of the arc comprising

step 1

Find the measure of arc EF

$m$

we have

$m$

substitute

$45\°=\frac{1}{2}(arc\ EF)$

$arc\ EF=90\°$

step 2

Find the measure of arc EH

$m$

we have

$m$

substitute

$49\°=\frac{1}{2}(arc\ EH)$

$arc\ EH=98\°$

step 3

Find the measure of arc FGH

$arc\ FGH=360\°-(arc\ EH+arc\ EF)$

substitute the values

$arc\ FGH=360\°-(98\°+90\°)$

$arc\ FGH=172\°$

step 4

Find the measure of angle FEH

$m$

we have

$arc\ FGH=172\°$

substitute

$m$

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Depending on what calculator you have, this should be pretty simple, divide the World lottery by her annual salary to determine how many times as large it is.
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2 years ago

Read 2 more answers

To support a shelf, the diameter of a bolt can measure anywhere from 0.2 cm less than 1.5 cm to 0.2 cm greater than 1.5 cm. Whic

Deffense [45]

Find min
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max is 0.2+1.5=1.7cm

so it would be a graph from 1.3cm to 1.7cm

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