Answer:
x=3 meters
Step-by-step explanation:
step 1
Find the area of the rectangular pool
we have
substitute
step 2
Find the area of rectangular pool including the area of the walkway
Let
x ----> the width of the walkway
we have
substitute
step 3
Find the area of the walkway
To find out the area of the walkway subtract the area of the pool from the area of rectangular pool including the area of the walkway
so
step 4
Find the value of x if the area of the walkway equal the area of the pool
so
Solve for x
Solve the quadratic equation by graphing
The solution is x=3 meters
see the attached figure
Step-by-step explanation:
Since we have given that
Number of muffins Diana sold at the bake sale = 336
Number of muffins Bob sold at the bake sale = 287
Now, here we are using the method of estimation i.e. rounding the integers to nearest ones.
By estimation, we get
Number of muffins Diana sold at the bake sale = 340
Number of muffins Bob sold at the bake sale = 290
So,
Difference between them is given by
Hence, Bob sold 50 fewer muffins than Diana.
You ended without giving the values, so we can't get the exact answer. However, I can tell you steps.
First, you need to find the z-score. Then, look up the z-score on a normal distribution table and you will get the percent.
Let's call your value X. Just plug X into the equation below and you will have your z-score.
(x - 20.5) / 3.5 = z
Now, look up the z-score and you will have your probability.<span />
Answer:
<LKJ = 115°
Step-by-step explanation:
<LKJ = <LKD + <DKJ
<LKJ = 60°+55°
<LKJ = 115°
Answered by GAUTHMATH
Answer:
The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.
Step-by-step explanation:
According to DeMorgan's Theorem:
(W.X + Y.Z)'
(W.X)' . (Y.Z)'
(W'+X') . (Y' + Z')
Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.
For the original function:
(W . X + Y . Z)'
= (1 . 1 + 1 . 0)
= (1 + 0) = 1
For the compliment:
(W' + X') . (Y' + Z')
=(1' + 1') . (1' + 0')
=(0 + 0) . (0 + 1)
=0 . 1 = 0
Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.
Without the parenthesis the compliment equation looks like this:
W' + X' . Y' + Z'
1' + 1' . 1' + 0'
0 + 0 . 0 + 1
Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.
Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.
