What is the upper quartile of the following set 28, 45, 12, 34, 36, 45, 19, 20
2 answers:
Answer:
Q3 = 40.5
Step-by-step explanation:
The first step to solve your exercise is ordering all the elements of the data set.
So the ordered data set is:
12, 19, 20, 28, 34, 36, 45, 45
The upper quartile is the median of the upper half of a data set. Mathematically, the upper quartile is the term at the position P defined by the equation below
This exercise data-set has a cardinality of 8, so n = 8.
So
However, P = 6.75. When the decimal part is .75, we subtract .25, so P = 6.50.
So, the upper qurtily is the average between the 6th and 7th terms in the ordered set.
Uq = Q3 = (45+36)/2 = 40.5
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So the right options are:
Further explanation:
Given equation of line is:
2x+5y=10
We have to convert it into point-slope form
The co-efficient of x is the slope of the line
So,
As the required line is parallel to given line, it will also have same slope.
Let m1 be the slope of required line
Then the line will be:
Putting the value of slope
Putting (-5,1) in the equation to find the value of b
Putting the values of slope and b in equation
Multiplying the whole equation by 5 will give us:
5y = -2x-5
2x+5y = -5
Another form of equation of line is Point-slope form
Putting the values of slope and point in the equation, we get
So the right options are:
Keywords: Point-Slope form, Parallel lines
Learn more about point slope form at:
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