All categories

2 years ago

how much material was used in the manufacture of 24000 celluloid dice,if each dice has an edge of 1/4 inches?

2 answers:

8 0

The volume of each celluloid die is (.25 x .25 x .25) = 0.015625 cubic inch.

To manufacture 24,000 of them, you need to start with at least

(24,000) x (0.015625) = 375 cubic inches.

I don't know how celluloid is sold, so you should also keep in mind that
375 cubic inches = about 207.8 fluid ounces, or about 6.5 quarts.

I'm sure a bit more than that was used in the manufacture, since
there's always some wasted, spilled, or trimmed off of the edges.

Anika [276]2 years ago

4 0

Material was used in the manufacture of 24000 celluloid dice
each dice has an edge of 1/4 inches
=1/4*24000
=24000/4
=6000
material was used in the manufacture of 24000 celluloid dice is 6000

You might be interested in

Which of the following companies offers the greatest total employment compensation? Company A Company B Company C Company D Gros

san4es73 [151]

we know that

To find the company with the greatest total employee compensation package, adds each company's gross pay, paid insurance, and paid time off, then subtract the job expenses on the sum

Find the total employee compensation package for each company

Step $1$

Find the total employee compensation package for company A

$total\ employee\ compensation=gross\ pay\ +\ paid\ insurance\ +\ paid\ time\ -\ job\ expenses$

$total\ employee\ compensation=37,600+2,800+3,100-1,200\\ total\ employee\ compensation=42,300\ dollars$

Step $2$

Find the total employee compensation package for company B

$total\ employee\ compensation=gross\ pay\ +\ paid\ insurance\ +\ paid\ time\ -\ job\ expenses$

$total\ employee\ compensation=36,800+2,400+3,600-600\\ total\ employee\ compensation=42,200\ dollars$

Step $3$

Find the total employee compensation package for company C

$total\ employee\ compensation=gross\ pay\ +\ paid\ insurance\ +\ paid\ time\ -\ job\ expenses$

$total\ employee\ compensation=38,100+2,100+2,900-300\\ total\ employee\ compensation=42,800\ dollars$

Step $4$

Find the total employee compensation package for company D

$total\ employee\ compensation=gross\ pay\ +\ paid\ insurance\ +\ paid\ time\ -\ job\ expenses$

$total\ employee\ compensation=39,000+1,800+2,500-800\\ total\ employee\ compensation=42,500\ dollars$

therefore

the answer is

the company with the greatest total employee compensation package is the company C

8 0

2 years ago

Read 2 more answers

Triangle A has a height of 2.5\text{ cm}2.5 cm2, point, 5, start text, space, c, m, end text and a base of 1.6\text{ cm}1.6 cm1,

konstantin123 [22]

Answer:

Option A

Option D

Option E

Step-by-step explanation:

we know that

If the height and base of triangle B are proportional to the height and base of triangle A

then

Triangle A and Triangle B are similar

Remember that

If two triangles are similar then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

$\frac{h_A}{h_B} =\frac{b_A}{b_B}$

where

h_A and h_B are the height of triangle A and triangle B

b_A and b_B are the base of triangle A and triangle B

In his problem we have

$h_A=2.5\ cm\\b_A=1.6\ cm$

substitute

$\frac{2.5}{h_B} =\frac{1.6}{b_B}$

Rewrite

$\frac{2.5}{1.6} =\frac{h_B}{b_B}$

$\frac{h_B}{b_B}=1.5625$

Verify all the options

A) we have

$h_B=2.75\ cm\\b_B=1.76\ cm$

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

$\frac{2.75}{1.76}=1.5625$

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

B) we have

$h_B=9.25\ cm\\b_B=9.16\ cm$

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

$\frac{9.25}{9.16}=1.0098$

The ratios are not equal

That means that are not proportional

therefore

These values could not be the height and base of triangle B

C) we have

$h_B=3.2\ cm\\b_B=5\ cm$

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

$\frac{3.2}{5}=0.64$

The ratios are not the same

That means that are not proportional

therefore

These values could not be the height and base of triangle B

D) we have

$h_B=1.25\ cm\\b_B=0.8\ cm$

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

$\frac{1.25}{0.8}=1.5625$

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

E) we have

$h_B=2\ cm\\b_B=1.28\ cm$

Find the ratio of the height to the base of triangle B and compare the result with the ratio of height to the base of triangle A (the value is 1.5625)

substitute the values in the proportion

$\frac{2}{1.28}=1.5625$

The ratios are the same

That means that are proportional

therefore

These values could be the height and base of triangle B

8 0

2 years ago

Write a expression that shows 3 times the sixth power of 10

user100 [1]

(10 raised to the power of 6)×3

(10*6) ×3

8 0

2 years ago

Monique planted seeds to grow pansies, Snapdragons, and petunias. After several weeks, 18 out of 40 pansy seeds, 21 out of 50 sn

OLEGan [10]

Answer:

petunias, snapdragons, then pansy

Step-by-step explanation:

Ok first, lets find the percentage of 18 out of 40: 18/40= 0.45

The 21 out of 50= 21/50= 0.42

Lastly, 12/30= 0.40

And its very simple to put from least to greatest:

0.40, 0.42, 0.45

Hope this helped ;)

7 0

2 years ago

Read 2 more answers

April and Sanjay are both using tools to simulate the probability that a family with three children will have exactly one girl.

azamat

The simulations have different theoretical probabilities of a 3-child family having exactly one girl, and the experimental probabilities they generate may differ.

8 0

2 years ago

Read 2 more answers