There are an infinite number of possibilities, but one of them could be 45/100 or 9/20
Divide the APR by 360 days and multiply it by 30 days to get the monthly interest. Each loan is usually secured by the car you bought. So we will use the secured APR.
8. Average rating secured apr: 5.85% divide by 360 multiply by 30: 0.4875% monthly rate
Cost of car: 19,725 ; sales tax: 4.75% ; down payment: 2,175
19,725 x 1.0475 = 20,661.94 - 2,175 = 18,486.94 loan amount
18,486.94 x 0.4875% = 90.12 accrued interest for the 1st month.
9. Excellent rating secured apr: 4.80% divide by 360 multiply by 30: 0.40% monthly rate
Cost of car: 15,867 ; sales tax: 5.25% ; down payment: 10% of total cost
15,867 x 1.0525 = 16,700.02 x 90% = 15,030.02 the principal balance at the start of the loan.
10. Fair rating secured apr: 7% divide by 360 multiply by 30: 0.5833% monthly rate
Cost of new car: 19,072 ; sales tax: 4.5% ; down payment: 1,200
Cost of used car: 15,365; sales tax: 4.5% ; down payment: 1,200
19,072 x 1.045 = 19,930.24 - 1,200 = 18,730.24
18,730.24 x 0.5833% = 109.25 accrued interest
15,365 x 1.045 = 16,056.43 - 1,200 = 14,856.43
14,856.43 x 0.5833% = 86.66 accrued interest
109.25 - 86.66 = 22.59 is the difference in interest accrued by the end of the first month.
Evaluate 4-0.25g+0.5h4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g=10g=10g, equals, 10 and h=5h=5h, equals,
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I believe the correct given equation is in the form of:
4 – 0.25 g + 0.5 h
Now we are to evaluate the equation with the given values:
g = 10 and h = 5
What this actually means is that to evaluate simply means
to calculate for the value of the equation by plugging in the values of the
variables. Therefore:
4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)
4 – 0.25 g + 0.5 h = 4 – 2.5 + 2.5
4 – 0.25 g + 0.5 h = 4
Therefore the value of the equation is:
4
Answer:
Step-by-step explanation:
The domain of a function is the set for which the function is defined. Our function is the function 
. This function is defined regardless of the value of x, so it is defined for every real value of x. That is, it's domain is the set {x|x is a real number}.
The range of the function is the set of all possible values that the function might take, that is {y|y=6x-4}. Recall that every real number y could be written of the form y=6x-4 for a particular x. So the range of the function is the set {y|y is a real number}.
Note that as x gets bigger, the value of 6x-4 gets also bigger, then it doesn't approach any particular number. Note also that as x approaches - infinity, the value of 6x-4 approaches also - infinity. In this case, we don't have any horizontal asymptote. Since the function is defined for every real number, it doesn't have any vertical asymptote. Since h is a linear function, it cannot have any oblique asymptote, then h doesn't have any asymptote.
