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BARSIC [14]
1 year ago
6

What are the domain, range, and asymptote of h(x) = 6x – 4? domain: {x | x is a real number}; range: {y | y > 4}; asymptote:

y = 4 domain: {x | x is a real number}; range: {y | y > –4}; asymptote: y = –4 domain: {x | x > –4}; range: {y | y is a real number}; asymptote: y = 4 domain: {x | x > 4}; range: {y | y is a real number}; asymptote: y = –4
Mathematics
2 answers:
Sladkaya [172]1 year ago
6 0

Answer:

the answer is b

Step-by-step explanation:

Mkey [24]1 year ago
4 0

Answer:

Step-by-step explanation:

The domain of a function is the set for which the function is defined. Our function is the function h(x) = 6x-4. This function is defined regardless of the value of x, so it is defined for every real value of x. That is, it's domain is the set {x|x is a real number}.

The range of the function is the set of all possible values that the function might take, that is {y|y=6x-4}. Recall that every real number y could be written of the form y=6x-4 for a particular x. So the range of the function is the set {y|y is a real number}.

Note that as x gets bigger, the value of 6x-4 gets also bigger, then it doesn't approach any particular number. Note also that as x approaches - infinity, the value of 6x-4 approaches also - infinity. In this case, we don't have any horizontal asymptote. Since the function is defined for every real number, it doesn't have any vertical asymptote. Since h is a linear function, it cannot have any oblique asymptote, then h doesn't have any asymptote.

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Your utility company charges 13 cents per kilowatt-hour of electricity. What is the daily cost of keeping lit a 75 watt light bu
Tresset [83]

we know that

1 Kw=1000 w

The company charges 13 cents per kilowatt-hour of electricity

13 cents=0.13 dollars\\\\ 75w=\frac{75}{1000} kw\\\\ 15w=\frac{15}{1000} kw

Step 1

Find the cost for the light bulb

a) in one day

\frac{75}{1000} *12=0.9\ kw\  hour

Cost=0.13*0.9

Cost=$0.117

b) In a year

\frac{75}{1000} *12=0.9\ kw\  hour

0.9*365=328.5\ kw\  hour

Cost=0.13*328.5

Cost=$42.71

Step 2

Find the cost for the led bulb

a) in one day

\frac{15}{1000} *12=0.18\ kw\  hour

Cost=0.13*0.18

Cost=$0.0234

b) In a year

\frac{15}{1000} *12=0.18\ kw\  hour

0.18*365=65.7\ kw\  hour

Cost=0.13*65.7

Cost=$8.54

Step 3

Find the difference in cost

Save=42.71-8.54\\ Save=34.17 dollars

therefore

the answer is

34.17 dollars

3 0
2 years ago
Read 2 more answers
The grade of a road is the slope of a road. In the U.S., grade is often expressed as a percent by finding the product 100(slope)
bagirrra123 [75]
The grade of a road is the slope of a road. In the U.S., grade is often expressed as a percent by finding the product 100(slope). Approximate the grade of a road that has a rise of 950 ft over 3 mi is :
A. 3%

6 0
1 year ago
In two or more complete sentences, describe the transformation(s) that take place on the parent function, f(x) = log(x), to achi
lubasha [3.4K]

Answer:

Shift 2 unit left

Flip the graph about y-axis

Stretch horizontally by factor 2

Shift vertically up by 2 units

Step-by-step explanation:

Given:

Parent function: f(x)=\log x

Transformation function: f(x)=\log(-2x-4)+2

Take -2 common from transform function f(x)

f(x)=\log[-2(x+2)]+2

Now we see the step-by-step translation

f(x)=\log x

Shift 2 unit left ( x → x+2 )

f(x)=\log(x+2)

Flip the graph about y-axis ( (x+2)  → - (x+2) )

f(x)=\log[-(x+2)]

Stretch horizontally by factor 2 [ -x(x+2) → -2(x+2) ]

f(x)=\log[-2(x+2)]

Shift vertically up by 2 units [ f(x) → f(x) + 2 ]

f(x)=\log[-2(x+2)]+2

Simplify the function:

f(x)=\log(-2x-4)+2

Hence, Using four step of transformation to get new function f(x)=\log(-2x-4)+2

3 0
2 years ago
Read 2 more answers
Identify the key characteristics of the parent fifth-root function f (x) = ^5sqrtx. Include the following: domain, range, interv
Andre45 [30]

Given functin is :

f\left(x\right)=\sqrt[5]{x}

We know that the domain of the expression is all real numbers except where the expression is undefined. In given function, there is no real number that makes the expression undefined. Hence domain is all real numbers.

Domain: (-∞,∞)

Range is the set of y-values obtained by plugging values from domain so the range will also same.

Range: (-∞,∞)

If we increase value of x then y-value will also increase so that means it is an INCREASING function. You can also verify that from graph.

It crosses x and y-axes both at the origin

Hence x-intercept=0 and y-intercept=0

Graph is not symmetric about y-axis hence it can't be EVEN

Graph is not symmetric about origin so it is ODD.

There is  no breaking point in the graph so that means it is a Continuous function.

There is no hoirzontal or vertical or slant line which seems to be appearing to touch the graph at infinity so there is NO asymptote.

END behaviour means how y-changes when x approaches infinity.

From graph we can see that when x-approaches -∞ then y also approaches ∞.

when x-approaches +∞ then y also approaches +∞.

7 0
2 years ago
What is the finance charge on $13,300 financed at 7.9 percent for 4 years if the monthly payment per $100 is $2.44?
luda_lava [24]

If you borrowed $100, then your monthly payment is $2.44

If you borrowed $200, then your monthly payment is 2*2.44 = 4.88

etc etc

We can set up a proportion

2.44/100 = x/13300

to figure out the monthly payment x. Cross multiply and solve for x

2.44*13300 = 100*x

100x = 2.44*13300

100x = 32452

x = 32452/100

x = 324.52

So the monthly payment is $324.52

An alternative way to get this monthly payment is to apply 2.44% to 13300, which is another way to view the phrase  "monthly payment per $100 is 2.44"

------------------

There are 48 months in 4 years (start with 12 mon = 1 yr, then multiply both sides by 4) so we multiply 48 by the monthly payment to get the result 48*324.52 = 15,576.96. This is the total amount you have to pay back which is the principal plus interest.

Subtract off the principal (amount borrowed) to find the interest or finance charge: 15,576.96 - 13,300 = 2,276.96

Answer: Choice B

5 0
2 years ago
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