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Anvisha [2.4K]
2 years ago
13

String a is 35 centimeters long. String b is five times as long as string a. Both are necessary to create a decorative bottle. F

ind the total length of string needed for 17 identical decorative bottle. Express your answer in meters.
Mathematics
1 answer:
gayaneshka [121]2 years ago
6 0

Answer:

35.7 m.

Step-by-step explanation:

To find the length of string b, you have to multiply 35 by 5. You get 175, and so when it asks how much total string you need for each bottle you must add 175 and 35, which gets you 210. Then, to find how much you need in total for 17 bottles  you need to multiply 210 by 17. This gets you 3570 cm, which you can convert to 35.7m.


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Josh's textbook reached the ground first by a difference of t=0.6482

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Before we proceed let us re write correctly the height equation which in correct form reads:

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We know that v_{o}=60ft/s

Thus Eqn. (2) becomes:

h(t)=-16t^2+60t+40        Eqn.(3)

<u>Josh:</u>

We know that v_{o}=48ft/s

Thus Eqn. (2) becomes:

h(t)=-16t^2+48t+40       Eqn. (4).

<em><u>Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at </u></em>h(t)=0<em><u>. Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one. </u></em>

Thus we have for Ben, Eqn. (3) gives:

h(t)=0-16t^2+60t+40=0

Using the quadratic expression to find the roots of the quadratic we have:

t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec

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t_{1}=3.6794sec\\t_{2}=-0.6794sec

Thus again we reject the negative and keep the positive solution, so Josh's book took t=3.6794 seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482

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<em>Whose textbook reaches the ground first and by how many seconds?</em>

  • Josh's textbook reached the ground first
  • Josh's textbook reached the ground first by a difference of t=0.6482

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