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mash [69]
2 years ago
12

There were 340,000 cattle placed on feed. Write an equivalent ratio that could be used to find how many of these cattle were bet

ween 700 and 799 pounds. How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?

Mathematics
2 answers:
BartSMP [9]2 years ago
6 0
2/5 = x/340,000

2 x 340,000 = 680,000

680,000 / 5 = 136,000

x = 136,000

136,000 cows were between 700 and 799 pounds


lutik1710 [3]2 years ago
3 0

There were 340,000 cattle placed on feed

How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?

Given the fraction of total cattle for 700 - 799 pounds is 2/5

Let x be the number of cattle between 700 - 799 pounds

We make a proportion using the fraction

\frac{2}{5} = \frac{x}{340,000}

Cross multiply it and solve for x

340000* 2 = 5x

680000 = 5x

Divide by 5 on both sides

So x= 136,000

There were 136,000 cattle between 700 and 799 pounds

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