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katovenus [111]
2 years ago
10

Sergio has ppp paintings in his art collection. He and other local painting collectors agreed to donate a total of 484848 painti

ngs to the local museum. Each of the 121212 collectors will donate the same number of paintings. How many paintings will Sergio have in his art collection after his donation?
Mathematics
2 answers:
Crazy boy [7]2 years ago
8 0

Answer:

484848

121212

±________

606,606

N76 [4]2 years ago
4 0

Answer:

p-4

Step-by-step explanation:

KHANACDEMY

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Seven students cut 5 and three-fourths inches of thread from a spool for a school project. What number represents the change in
Kitty [74]

Answer:

3

Step-by-step explanation:

4 0
1 year ago
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Katie buy a necklace for $14.50 plus a 6% tax, Sharon buys a bracelet for $12 plus a 6%tax.
UNO [17]

Answer:

28.09 for both including taxes

Step-by-step explanation:

6% of $14.50 is $0.87. 6% of $12 is $0.72. Together the values add up to $28.09.

5 0
1 year ago
Mr. mole left his burrow that lies 7 meters below the ground and started digging his way deeper into the ground, descending at a
Keith_Richards [23]

Answer:

A(t)=−1.8t−4.5

Step-by-step explanation:

Mr. Mole is descending at a constant rate, so we are dealing with a linear relationship.

We know that Mr. Mole descended at a rate of 1.81.81, point, 8 meters per minute, so the slope \green mmstart color green, m, end color green is \green{-1.8}−1.8start color green, minus, 1, point, 8, end color green, and our function looks like A(t)=\green{-1.8}t+\pink bA(t)=−1.8t+bA, left parenthesis, t, right parenthesis, equals, start color green, minus, 1, point, 8, end color green, t, plus, start color pink, b, end color pink.

We also know that after 555 minutes, Mr. Mole was 13.513.513, point, 5 meters below the ground, which means that A(5)=-13.5A(5)=−13.5A, left parenthesis, 5, right parenthesis, equals, minus, 13, point, 5. We can substitute this into the formula of the function to find \pink bbstart color pink, b, end color pink:

\qquad\begin{aligned}A(5)&=-13.5\\ \green{-1.8}\cdot5+\pink b&=-13.5\\ -9+\pink b&=-13.5\\ \pink b&=\pink{-4.5}\end{aligned}  

A(5)

−1.8⋅5+b

−9+b

b

​    

=−13.5

=−13.5

=−13.5

=−4.5

​  

This means that Mr. Mole's initial altitude is 4.54.54, point, 5 meters below the ground.

AKA the answer is A(t)=−1.8t−4.5

3 0
2 years ago
robin is making bead necklaces she want to use 717 beads to make 57 necklaces. if she wants each necklaces to have the same numb
EleoNora [17]

717=12\cdot684+33

<u>33 beads</u>

7 0
2 years ago
The aquarium at Sea Critters Depot contains 140 fish. Eighty of these fish are green swordtails (44 female and 36 male) and 60 a
maxonik [38]

Given that:

Total number of fish = 140

Fish are green swordtails female = 44

Fish are green swordtails male = 36

Fish are orange swordtails female = 36

Fish are orange swordtails male = 24

Solution:

A. We have to find the probability that the selected fish is a green swordtail.

\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}

\text{P(green swordtail)}=\dfrac{80}{140}

\text{P(green swordtail)}=\dfrac{4}{7}

Therefore, the probability that the selected fish is a green swordtail is \dfrac{4}{7}.

B.  We have to find the probability that the selected fish is male.

\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}

\text{P(Male fish)}=\dfrac{36+24}{140}

\text{P(Male fish)}=\dfrac{60}{140}

\text{P(Male fish)}=\dfrac{3}{7}

Therefore, the probability that the selected fish is a male, is \dfrac{3}{7}.

C. We have to find the probability that the selected fish is a male green swordtail.

\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}

\text{P(Male green swordtail)}=\dfrac{36}{140}

\text{P(Male green swordtail)}=\dfrac{9}{35}

Therefore, probability that the selected fish is a male green swordtail is \dfrac{9}{35}.

D.

We have to find the probability that the selected fish is either a male or a green swordtail.

\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}

\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}

\text{P(Male or green swordtail)}=\dfrac{96}{140}

\text{P(Male or green swordtail)}=\dfrac{24}{35}

Therefore, the probability the selected fish is either a male or a green swordtail is \dfrac{24}{35}.

4 0
2 years ago
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