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Lubov Fominskaja [6]
2 years ago
13

Steven Kellogg, a jet airplane mechanic, works at an hourly rate of

Mathematics
1 answer:
lozanna [386]2 years ago
3 0

Answer:

Part a) The straight-time pay is \$1,332

Part b) The overtime  pay is \$432

Part c) The total pay is \\$1,764

Step-by-step explanation:

Part a) What is his straight-time  pay?

To find out his straight-time  pay multiply the hourly rate of $36 by 37 hours worked

so

(36)(37)=\$1,332

Part b) What is his overtime  pay?

we know that

The hourly rate for overtime is equal to

(1.5)(36)=\$54

so

Multiply the hourly rate for overtime by the number of hours overtime

(54)(8)=\$432

Part c) What is his total pay?

we know that

The total pay is equal to sum the straight-time  pay plus the overtime  pay

\$1,332+\$432=\$1,764

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2 years ago
Find the coordinates of the center of the following circle. (x + 3)2 + (y - 6)2 = 24
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4 0
2 years ago
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A rectangular tank measuring 35 cm by 28 cm by 16 cm is 2/5 filled with
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Answer:

Amount of water left in tank = 440 cm³

Step-by-step explanation:

Given:

Sides of tank respectively = 35 cm , 28 cm , 16 cm  

Water level in tank = 2/5

Side of a cubic tank = 18 cm

Find:

Amount of water left in tank

Computation:

Volume level in rectangular tank = [2/5][35 x 28 x 16]

Volume level in rectangular tank = [2/5][15,680]

Volume level in rectangular tank = [31,360/5]

Volume level in rectangular tank = 6,272 cm³

Volume of cube = side³

Volume of cube = 18³

Volume of cube = 5,832 cm³

Amount of water left in tank = Volume level in rectangular tank - Volume of cube

Amount of water left in tank = 6,272 - 5,832

Amount of water left in tank = 440 cm³

7 0
1 year ago
Bob has 40 cents in his pocket. If Bob has no pennies, how many different combinations of quarters, dimes, and/or nickles does h
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Answer:

He could have 4 dimes, or 8 nickles, or 1 quater and 3 nickels, or 1 quater with one dime and 1 nickel, or 3 dimes and 2 nickles, or 1 quater with obe nickel and one dime.

Step-by-step explanation:

hope this helps.

3 0
2 years ago
If f(1) = 0 what are all the roots of the function f(x)=x^3+3x^2-x-3 use the remainder theorem.
ArbitrLikvidat [17]

Solution:

As we are given that f(1) = 0 .

It mean that (x-1) is one of the factor of the given equation.

Remainder theorem can be applied as below:

\frac{(x^3+3x^2-x-3)}{(x-1)}=\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}\\ \\\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}=\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)} \\\\\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)}=\frac{(x^2+4x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+4x+3)(x-1)}{(x-1)} =\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  =\frac{(x-1)(x+3)(x+1)}{(x-1)}

Hence the factors are (x-1),(x+3) and (x+1).

Hence the correct option is B.

5 0
2 years ago
Read 2 more answers
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