Consider the graph of f(x) given below.

Which of the following statements must be true about this diagram? Check all that apply.

pishuonlain [190]

Answer:

Options (D), (E) and (F) are the correct options.

Step-by-step explanation:

From the figure attached,

1). Angle 4 is the exterior angle of the given triangle having interior angles 1, 2 and 3.

Therefore, by the property of exterior angle,

∠4 = ∠1 + ∠2

2). Since ∠4 = ∠1 + ∠2,

Therefore, ∠4 will be greater than ∠1

Similarly, ∠4 will be greater than ∠2

Therefore, Options (D), (E) and (F) are the correct options.

8 0

1 year ago

Leo and Maggie volunteer at the local bird sanctuary. Volunteers carry walkie-talkies. Leo notices that his walkie-talkie’s batt

Fiesta28 [93]

12 * 20% = 12 * 0.20 = 2.4 hours

It will not last his entire shift.

5 0

2 years ago

Antawn Jamison is shooting free throws. Making or missing free throws doesn't change the probability that

scoray [572]

Answer: 0.73^9

Step-by-step explanation: Khan

5 0

2 years ago

. James has 16 ounces (oz.) of cookie dough. If he uses 0.56 oz. of cookie dough for each

Anna71 [15]

Step-by-step explanation:

<u>Step 1: Find the reasonable estimate</u>

<u /> $Total\ Amount\ of\ Dough / Dough\ Per\ Cookie$

$16 / 0.56$

$28.571...$

The closest number to 28 out of the option is 30. Therefore, the correct option is D.

Answer: Option D

6 0

2 years ago

Read 2 more answers

From past experience, a company has found that in carton of transistors: 92% contain no defective transistors 3% contain one def

jasenka [17]

Answer:

$E(X) = 0*0.92 + 1*0.03 +2*0.03 +3*0.02 = 0.1500$

In order to find the variance we need to find first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = 0^2*0.92 + 1^2*0.03 +2^2*0.03 +3^2*0.02 = 0.3300$

The variance is calculated with this formula:

$Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075$

And the standard deviation is just the square root of the variance and we got:

$Sd(X) = \sqrt{0.3075}= 0.5545$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

LEt X the random variable who represent the number of defective transistors. For this case we have the following probability distribution for X

X 0 1 2 3

P(X) 0.92 0.03 0.03 0.02

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) = 0*0.92 + 1*0.03 +2*0.03 +3*0.02 = 0.1500$

In order to find the variance we need to find first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = 0^2*0.92 + 1^2*0.03 +2^2*0.03 +3^2*0.02 = 0.3300$

The variance is calculated with this formula:

$Var(X) = E(X^2) -[E(X)]^2 = 0.33 -(0.15)^2 = 0.3075$

And the standard deviation is just the square root of the variance and we got:

$Sd(X) = \sqrt{0.3075}= 0.5545$

8 0

2 years ago