Answer:
The GCF of the coefficients is correct.
The variable c is not common to all terms, so a power of c should not have been factored out.
In step 6, David applied the distributive property.
Step-by-step explanation:
Given the polynomial :
80b⁴ – 32b²c³ + 48b⁴c
The Greatest Common Factor (GCF) of the coefficients:
80, 32, 48
Factors of :
80 : 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80
32 : 1, 2, 4, 8, 16, and 32
48 : 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.
GCF = 16
b⁴, b², b⁴
b⁴ = b * b * b * b
b² = b * b
b⁴ = b * b * b * b
GCF = b*b = b²
GCF of c³ and c
c³ = c * c * c
c = c
GCF = c
We can see that David's GCF of the coefficients are all correct
From the polynomial ; 80b⁴ does not contain c ; so factoring out c is incorrect
In step 6 ; the distributive property was used to obtain ; 16b²c(5b² – 2c² + 3b²)
Answer:
Step-by-step explanation:
Let
r ----> the number of readers (y-coordinate or dependent variable)
t ----> the number of years after 2000 (x-coordinate or independent variable)
Remember
2004 ----> represent t=4 years
2014 ----> represent t=14 years
we have the ordered pairs
(4,1,000,000) and (14,2,000,000)
step 1
Find the slope
The formula to calculate the slope between two points is equal to
substitute the values
step 2
Find the equation of the line in point slope form
we have
substitute
step 3
Convert to slope intercept form
isolate the variable r
step 4
Convert to function notation
Answer:It is important to record each transaction so Bob knows how much money is in his account. That prevents being overdrawn. Recording debits and deposits helps with budgeting. It is good to keep receipts in case of any bank errors.
Step-by-step explanation:
Answer:
1/4h
Step-by-step explanation:
If the time for the car trip is x, then given that a car trip is 1/2h shorter than a bus trip, it means that adding 1/2h to the time for a car trip gives the time for the bus trip.
Hence, the time for the bus trip
= (1/2 + x)h
since the bus trip is 3/4h, it means that
1/2 + x = 3/4
collecting like terms,
x = 3/4 - 1/2
= 3/4 - 2/4
= 1/4
Hence the car trip is 1/4h.
A = {1, 2, 5, 6, 8}
{1} U {2, 5, 6, 8}
{2} U {1, 5, 6, 8}
{5} U {1, 2, 6, 8}
{6} U {1, 2, 5, 8}
{8} U {1, 2, 5, 6}
{1, 2} U {5, 6, 8}
{1, 5} U {2, 6, 8}
{1, 6} U {2, 5, 8}
{1, 8} U {2, 5, 6}
{1, 2, 5} U {6, 8}
{1, 2, 6} U {5, 8}
{1, 2, 8} U {5, 6}
{1, 5, 6} U {2, 8}
{1, 5, 8} U {2, 6}
{1, 6, 8} U {2, 5}
The answer is 15 distinct pairs of disjoint non-empty subsets.
