Answer:
7boxes
Step-by-step explanation:
A box can hold a maximum of 8 cans
You have a total of 50 cans
The problem here is to determine the minimum number of boxes that can hold the 50 cans
Let the minimum number of boxes = y
The minimum required will be such that:
The Product of The number of cans X Number of Required boxes ≥50
8y≥50
y≥50/8
y≥6.25
Since a box have a fractional value, the minimum number of boxes required to store 50 cans will be the nearest whole number which in this case is 7.
Answer:
The values of a and b are {12,13}
Step-by-step explanation:
As,
We convert the division into a multiplication by inverting the denominator
Therefore, the smallest possible non-negative whole numbers for a and b could be are 12 and 13, respectively.
Answer: 31 : 9
Step-by-step explanation:
Assume the following:
Alice's amount = P
Bob's amount = Q
Amount received = n
If Alice receives $n$ dollars from Bob ;then she will have $4$ times as much money as Bob.
P + n = 4(Q - n)
P + n = 4Q - 4n
P = 4Q - 4n - n
P = 4Q - 5n - - - - (1)
If, on the other hand, she gives $n$ dollars to Bob, then she will have $3$ times as much money as Bob
P - n = 3(Q + n)
P - n = 3Q + 3n
P = 3Q + 3n + n
P = 3Q + 4n - - - - - - (2)
Equating both equations - (1) and (2)
4Q - 5n = 3Q + 4n
4Q - 3Q = 4n + 5n
Q = 9n
Express P in terms of n, use either equation (1) or (2)
From equation 2:
P = 3Q + 4n
Substituting Q = 9n
P = 3(9n) + 4n
P = 27n + 4n
P = 31n
Alice's amount = P, Bob's = Q
Ratio = P:Q
31 : 9
Answer:
$2.24
Step-by-step explanation:
The shipping cost for one package was 1/11 of the total shipping cost.
... 1/11 · $24.64 = $2.24
Answer:
648 followers
Step-by-step explanation:
Let first day=a1
Tripled followers everyday
Second day=a2=a1×3
Third day=a3=a2*3
Fourth day=a4=a3*3
Fifth day=a5=a4*3
a=8 followers
a2=a1×3
=3*8
=24 followers
a3=a2*3
=24*3
=72 followers
a4=a3*3
=72*3
=216 followers
a5=a4*3
=216*3
=648 followers
On the fifth day, Alex will have a total of 648 followers on his new social media account.
