Answer:
Number of rectangles could alex draw with an area of 11cm² = 1
Step-by-step explanation:
Minimum length in centimeter grid = 1 cm
Alex is drawing rectangles with different areas on a centimetre grid.He can draw 3 different rectangles with an area of 12cm²
That is
These are the 3 different rectangles with an area of 12cm².
Now we need to find how many rectangles could alex draw with an area of 11cm².
11 = 1 x 11
So only one factorization is possible.
Number of rectangles could alex draw with an area of 11cm² = 1
B. every member of the boys' basketball team
because people who play basketball are generally taller which means they have bigger feet (most of the time) which doesn't accurately represent the average of the male student body.
Answer:
When x = 15, y= 2
When y= 10, x= 3
Step-by-step explanation:
This is a question in inverse proportion. In this proportion, an increase in one quantity would lead to a decrease in the other and vice versa.
We are to complete the table using the relationship between x and y.
Given:
y is inversely proportional to x = y ∝ 1/x
∝ = proportional to
y ∝ 1/x
y = k × 1/x
Where k = constant of proportionality
To understand the relationship between y and x, we need to find the value of k.
y = k × 1/x
From the table,
When x = 6, y = 5
5 = k × 1/6
5 = k/6
k = 6×5 = 30
y = 30 × 1/x
y = 30/x
The above relationship would enable us find the missing parts.
When x = 15, y= ?
y = 30/15
y = 2
When y= 10, x= ?
10 = 30/x
10x = 30
x = 30/10
x= 3
<h2>Answer:</h2>
A.
Let Annie's weight be = a
Let Benjie's weighs = b
Let Carmen's weight be = c
One day Annie weighed 24 ounces more than Benjie, equation forms:
......(1)
Benjie weighed 3 1/4 pounds less than Carmen.
In ounces:
1 pound = 16 ounces
pounds = 
ounces
or
......(2)
Now adding (1) and (2), we get
a+b=b+24+c-52
=> 
This gives Annie weighs 28 ounces less than Carmen.
B.
We cannot know anyone's actual weight, as we only know their relative weights.
We have to choose the correct answer for the center of the circumscribed circle of a triangle. The center of the circumscribed circle of a triangle is where the perpendicular bisectors of a triangle intersects. In this case P1P2 and Q1Q2 are perpendicular bisectors of sides AB and BC, respectively and they intersect at point P. S is the point where the angle bisectors intersect ( it is the center of the inscribed circle ). Answer: <span>P.</span>
