The following data shows the low temperature in Vancouver, in degrees Celsius, for two weeks in January one year. 8.90, 8.35, 8.
40, 8.40, 8.50, 8.20, 8.50, 8.32, 8.50, 8.50, 8.60, 8.30, 8.10, 8.65 Which box plot best represents this data?
1 answer:
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Answer:
The median and mode of the students grade is 70.
Most of the students scored between 40 and 100.
Step-by-step explanation:
From the provided information it can be seen that the mean of the distribution is, <em>μ</em> = 70 and the standard deviation is, <em>σ</em> = 15.
For a Normal distributed data the mean, median and mode are the same.
So, the median and mode of the students grade is 70.
The standard deviation of the data represents the spread of the observation, i.e. how dispersed the values are along the curve.
In statistics, the 68–95–99.7 rule, also recognized as the empirical rule, is a shortcut used to recall that 68.27%, 95.45% and 99.73% of the values of a Normally distributed data lie within one, two and three standard deviations of the mean, respectively.
Assuming that maximum marks of the exam is 100, it can be said that most of the students scored between 40 and 100.
Alright, lets get started.
The foreign exchange rate between the japanese yen and the euro is 190:1 given.
It means 1 euro = 190 yen
We are asked to find how many yen will be equal to 10 euros.
Means we need to multiply given euros with 190 because 1 euro = 190 yen
Hence 10 euros yen
10 euros = 1900 yen : Answer
Hope it will help :)