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Crank
1 year ago
11

A meteorologist is studying the monthly rainfall in a section of the Brazilian rainforest. She recorded the monthly rainfall, in

inches, for last year. They were:
1.8, 2.5, 2.6, 4.4, 4.4, 7.3, 8.0, 9.5, 10.3, 10.4, 11.1, 11.7

For this data set:

Mu = 7, N = 12. Sigma squared = StartFraction (x 1 minus mu) Squared + (x 2 minus mu) squared + ellipsis + (x N minus mu) squared Over N EndFraction. Sigma squared = StartFraction (1.8 minus 7) squared + (2.5 minus 7) squared + ellipsis + (11.7 minus 7) squared Over 12 EndFraction
Fill in the missing values in the formula. What is the variance?



please help
Mathematics
2 answers:
Mariana [72]1 year ago
7 0

Answer:

12.405

Step-by-step explanation:

edge2020

aleksandr82 [10.1K]1 year ago
3 0

Answer:

12.405

Step-by-step explanation:

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*NO 194 39% 13:08 Pilih jawaban yang paling tepat Segitiga PQR dan segitiga XYZ 5 poin merupakan dua segitiga yang kongruen. Bes
Illusion [34]

Answer:

Option d. PQ = YZ

Step-by-step explanation:

<u><em>The question in English is</em></u>

Choose the most appropriate answer. The PQR triangle and the XYZ triangle are two congruent triangles. The angle P = the angle Y and PR = YX. Side pairs of the same length are ... a. PQ = XZ b. QR = YZ c. QR = XY d. PQ = YZ

we know that

If two triangles are congruent, then its corresponding sides and its corresponding angles are congruent

Corresponding sides are named using pairs of letters in the same position on either side of the congruence statement

so

we have that

m\angle P=m\angle Y

PR=YX

so

Triangle PQR is congruent with Triangle YZX

That means

<em><u>Corresponding angles</u></em>

m\angle P=m\angle Y

m\angle Q=m\angle Z

m\angle R=m\angle X

<u><em>Corresponding sides</em></u>

PQ=YZ\\QR=ZX\\PR=YX

8 0
1 year ago
Point B is in the interior of ∠AOC, m∠AOC = 108°, m∠AOB = 3m∠BOC. Find m∠AOB.
valentinak56 [21]
If point is the interior of <AOC ,
 then m<AOB + m<BOC = m< AOC    (  angle addition postulate )         eq 1
          (3m<BOC )  +   m <BOC  = m <AOC   {   m<AOB =  3m<BOC)
              4m <BOC  =    108  
                   m<BOC  =    27 

      m<AOB + m <BOC =  m < AOC 
       m<AOB  =   108 - 27 
        m <AOB  =    81 





6 0
2 years ago
Read 2 more answers
A study was conducted to determine the mean birth weight of a certain breed of kittens. Consider the birth weights of kittens to
kipiarov [429]
3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.
7 0
1 year ago
Given: AD ≅ BC and AD ∥ BC Prove: ABCD is a parallelogram. Statements Reasons 1. AD ≅ BC; AD ∥ BC 1. given 2. ∠CAD and ∠ACB are
ira [324]

 Given: AD ≅ BC and AD ∥ BC

Prove: ABCD is a parallelogram.

 Statements                                                                 Reasons

 1. AD ≅ BC; AD ∥ BC                                              1. given

 2. ∠CAD and ∠ACB are alternate interior ∠s          2. definition of alternate                                                                                    interior angles

3. ∠CAD ≅ ∠ACB                                                    3. alternate interior                                                                                          angles are congruent

4. AC ≅ AC                                                              4. reflexive property

 5. △CAD ≅ △ACB                                                  5. SAS congruency                                                                                                   theorem

6. AB ≅ CD                                                            6. Corresponding Parts                                                                                   of Congruent triangles are                                                                               Congruent (CPCTC)

7. ABCD is a parallelogram                                  7. parallelogram side                                                                                         theorem

<span> </span>

5 0
1 year ago
Read 2 more answers
The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding
Andru [333]

Answer:

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Step-by-step explanation:

Values (x) ∑(Xi-X)^2

----------------------------------

29.1                    0.1702

28.5                  1.0252

28.8                  0.5077

29.4                   0.0127

29.8                  0.0827

29.8                  0.0827

30.1                   0.3452

30.6                   1.1827

----------------------------------------

236.1                 3.4088

Mean = 236.1 / 8 = 29.51

S_{x}=\sqrt{3.4088/(8-1)}=0.6978

Statement of the null hypothesis:

H0: u ≥ 30 the mean wedding cost is not less than $30,000

H1: u < 30 the mean wedding cost is less than $30,000

Test Statistic:

t=\frac{X-u}{S/\sqrt{n}}=\frac{29.51-30}{0.6978/\sqrt{8}}= \frac{-0.49}{0.2467}=-1.9861

Test criteria:

SIgnificance level = 0.05

Degrees of freedom = df = n - 1 = 8 - 1 = 7

Reject null hypothesis (H0) if

t

Finding in the t distribution table α=0.05 with df=7, we have

t_{0.05,7}=2.365

t>-t_{0.05,7} = -1.9861 > -2.365

Result: Fail to reject null hypothesis

Conclusion: Do no reject the null hypothesis

u ≥ 30 the mean wedding cost is not less than $30,000

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Hope this helps!

5 0
2 years ago
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