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2 years ago

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Which statement correctly describes the slope of the linear function that is represented by the data in the table? x y 8 –8 8 –4

8 0 8 4 8 8 The slope is positive. The slope is negative. The slope is zero. There is no slope.

2 answers:

spin [16.1K]2 years ago

5 0

Answer:

Step-by-step explanation:

slope=change in y/change in x

one way is t pick 2 points, (x1,y1) and (x2,y2)

the slope is (y2-y1)/(x2-x1)

pick some points

(8,4) and (8,0)

slope=(0-4)/(8-8)=-4/0=undefined

the slope is undefined

there is no slope.

Juliette [100K]2 years ago

4 0

Answer:

there is no slope

Step-by-step explanation:

i did the quiz

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Alex17521 [72]

Answer:

a) $X=3300$

b) $Y=7770$

Step-by-step explanation:

From the question we are told that:

Number Teachers $T=6$

Number Student $S=12$

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a) Generally the equation for exactly 3 students on the committee is mathematically given by

$X=^{S}C_3*^{T}C_3$

$X=^{12}C_3*^{6}C_3$

$X=3300$

b) Generally the equation for at least one teacher and at least one student on the committee is mathematically given by

Total Ways-(no of ways of selection no teacher or student)

Where total Ways

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$T=8568$

Therefore

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$Y=8568-798$

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2 years ago

What is the true solution to the equation below?

jarptica [38.1K]

Answer:

Step-by-step explanation:

some rules of logarithmic function

$ln(a) - ln(b)=ln(\frac{a}{b})$

$e^{ln(a)}=a$

$ln(a)^{n}=nln(a)$ vice-versa $nln(a)=ln(a)^{n}$

If ㏑(a) = ㏑(b), then a = b

∴ $2ln(e^{ln(2x)})-ln(e^{ln(10x)})=ln(30)$

Use the 2nd rule to simplify it

$e^{ln(2x)}=2x\\e^{ln(10x)}=10x\\$

2㏑(2x) - ㏑(10x) = ㏑(30)

Use the 3rd rule in the 1st term

∵ 2㏑(2x) = ㏑(2x)² = ㏑(4x²)

∴ ㏑(4x²) - ㏑(10x) = ㏑(30)

- Use the 1st rule with the left hand side

$ln(4x^{2})-ln(10x)=ln(\frac{4x^{2}}{10x})\\\\ln(\frac{4x^{2}}{10x})=ln(30)\\\\ \frac{4x^{2}}{10x}=\frac{2x}{5}=\frac{2}{5}x\\\\ ln(\frac{2}{5}x)=ln(30)$

Use the 4th rule

$\frac{2}{5} x = 30$

Multiply both sides by 5

∴ 2 x = 150

- Divide both sides by 2

∴ x = 75

The value of x = 75

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Answer:

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Answer:

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Based on the table:

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