Ask question

Ask question

All categories

geniusboy [140]

2 years ago

15

Your starting and ending points will be just inch apart.if you draw a line seven inches left, three inches up, two inches right,

four inches down and ......?.........inches right.

1 answer:

kykrilka [37]2 years ago

4 0

I believe your asking either a. What is the next step. or b. What shape does it make?

Well. A, Take a ruler and do what it states, and b. what shape does it make? Well do step a.. but completing it.

Need any more help?

Hope this helped!

~Korey

You might be interested in

Mark and his friends ordered two pizzas are the same size the first pizza is cut into six slices of equal size the second pizza

tino4ka555 [31]

1/6 < 1/4 so 1/6 would equal 2/12 and 1/4 would equal 3/12 so which means if you take one from each it would be 5/12 but if you took 2 from the first one it would only be 2/12 which is why you need to read correctly because THE REASON MARK IS CORRECT IS BECAUSE 5/12 IS GREATER THAN 2/12

3 0

2 years ago

Adam is using the equation (x)(x + 2) = 255 to find two consecutive odd integers with a product of 255. When Adam solves the pro

kondaur [170]

$\bf (x)(x+2)=255\implies x^2+2x=255\implies x^2+2x-255=y
\\\\
\textit{setting y=0}\implies x^2+2x-255=0
\\\\
\textit{now, factoring that}
\\\\
(x+17)(x-15)=0\implies 
\begin{cases}
x=-17\\
x=15
\end{cases}$

notice the picture of the graph added here
low and behold, x = -17, y is 0, and x= 15, y is 0
the graph is touching the x-axis, an x-intercept
or so-called, a "solution"

3 0

2 years ago

Read 2 more answers

In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t

victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The probability that he or she would choose the pair of socks in the center position is $p =\frac{1}{5}$

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5

b

The mean is $\mu = 20$

The standard deviation is $\sigma=4$

c

The probability, $P =0.0002$

d

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability $Pe = 0.0003$

The probabilities $P \approx Pe$

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

$p =\frac{1}{5}$

$=0.2$

The mean of this distribution is mathematical represented as

$\mu = np$

substituting the value

$\mu = 100 * 0.2$

$\mu = 20$

The standard deviation is mathematically represented as

$\sigma = \sqrt{np (1-p)}$

substituting the value

$= \sqrt{100 * 0,2 (1-0.2)}$

$\sigma=4$

Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

$P=P(X \ge 34 )$

By standardizing the normal approximation we have that

$P(X \ge 34) \approx P(Z \ge z)$

Now z is mathematically evaluated as

$z = \frac{x-\mu}{\sigma }$

Substituting values

$z = \frac{34-20}{4}$

$=3.5$

So using the z table the $P(Z \ge 3.5)$ is 0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

6 0

2 years ago

We went to the market to buy some fruit. We decided to buy some apples, strawberries, and oranges. If we buy 2 apples, 3 boxes o

Ksivusya [100]

Step-by-step explanation:

Let the amount of apples bought be x

Amount of strawberries bought be y and;

amount of oranges bought be z

If we buy 2 apples, 3 boxes of strawberry, and 4 oranges, the fruit would cost $15.30, then this will be expressed as;

2x+3y+4z = 15.30 ........... 1

If we buy 1 box of strawberry, 4 apples, and 2 oranges, the fruit would cost $10.90, this will be expressed as:

4x+y+2z = 10.90 ......... 2

If we buy 1 orange, 5 apples and 2 boxes of strawberry, the fruit would cost $13.70, this is expressed as:

5x+2y+x = 13.70 .......... 3

Solving the three equations simultaneously:

2x+3y+4z = 15.30 ........... 1

4x+y+2z = 10.90 ......... 2

5x+2y+z = 13.70 .......... 3

Reduce the number of equations

multiply equation 1 by 2 and subtract from equation 2

equation 1 * 2 will give:

4x+6y+8z = 30.6 ........... 4

eqn (4)-eqn(2)

6y-y + 8z-2z = 30.6-10.90

5y+6z = 19.7 ......... 5

Also multiply equation 2 by 5 and eqn 5 by 4 and subtract from each other.

eqn(2)* 5 will give:

20x+5y+10z = 54.5 .......... *

eqn(3) * 4 will give

20x+8y+4z = 54.8.......**

Subtsrct ** from *

8y-3y+(4z-10z)= 54.8-54.5

5y-6z = 0.3 .................. 6

Equate 5 and 6 and solve:

5y+6z = 19.7 ......... 5

5y-6z = 0.3 .................. 6

subtract:

6z+6z = 19.7+0.3

12z = 20

z = 20/12

z = 1.67

Substitute z = 1.67 into eqn 6

5y-6(1.67) = 0.3

5y - 10 = 0.3

5y = 10.3

y = 10.3/5

y = 2.06

Substitute z = 1.67 and y = 2.06 into equation 1

From 1:

2x+3y+4z = 15.30

2x+3(2.06)+4(1.67) = 15.30

2x+6.18+6.68 = 15.30

2x+12.86 = 15.30

2x = 15.30-12.86

2x = 2.44

x = 2.44/2

x = 1.22

<em>Therefore 1 apple costs $1.22, 1 strawberry costs $2.06 and 1 orange costs $1.67</em>

3 0

2 years ago

vegetable ghee is stored in the cylindrical vessel of internal radius 1.4m height 1.5m. if it is transferred into the rectangula

irina1246 [14]

Answer:

<em>5,598 cans are required to empty the vessel</em>

Step-by-step explanation:

The volume of a cylinder of radius r and height h is:

$V = \pi r^2h$

The volume of a box of dimensions X, Y, and Z is:

V=X.Y.Z

A cylinder of r=1.4 m and height h=1.5 is used to store vegetable ghee. It contains a volume of:

$V_1 = \pi 1.4^2*1.5$

$V_1=9.236\ m^3$

Converting to cubic cm:

$V_1=9.236*1,000,000\ cm^3$

$V_1=9,236,282\ cm^3$

The volume of each rectangular tin can is:

$V_2=33*10*5=1,650\ cm^3$

$V_2=1,650\ cm^3$

The number of cans required to empty the vessel is:

$V_1/V_2=9,236,282/1,650 = 5,598$

5,598 cans are required to empty the vessel

5 0

2 years ago