Answer:
a) This is an Observational Study because in this kind of study investigators observe subjects and measure variables of interest without assigning treatments to the subjects. Here, the Gilham et al. (2005) studied two different groups where no treatment or intervention was done. These groups were independent of each other.
b) proportions of children with significant social activity in children with acute lymphoblastic leukemia = 1020/1272 = 0.80
proportions of children with significant social activity in children without acute lymphoblastic leukemia = 5343/6238 = 0.86
c) Odds ratio can be calculated using the following formula:
OR= \frac{a/b}{c/d}
where: a - Number in exposed group with positive outcome(here this means number of children with significant social activity associated with acute lymphoblastic leukemia)
b- Number of children without social activity having with acute lymphoblastic leukemia
c- Number of children with social activity having without acute lymphoblastic leukemia
d- Number of children without social activity having without acute lymphoblastic leukemia
OR= \frac{1020/252}{5343/895}
OR= 0.6780
d) The 95% confidence interval of this Odds Ratio is 0.5807 to 0.7917.
e) Since the odds ratio lies in this confidence interval indicate that the amount of social activity is associated with acute lymphoblastic leukemia. The children with more social activity have a higher occurrence of acute lymphoblastic leukemia.
Answer:
The value of x is 4.
Step-by-step explanation:
It is given that triangle MRN is created when an equilateral triangle is folded in half.
It means original equilateral is triangle MNO and NR is a perpendicular bisector (<em>A line which cuts a line segment into two equal parts at 90°</em>).
The side length of the triangle is
NO = NS + SM = 6 + 2 = 8
Since an equilateral triangle is a triangle in which all three sides are equal and NR is a perpendicular bisector, therefore
RM = MO/2 = 8/2 = 4
The value of x is 4.
Answer:
208,606,320
Step-by-step explanation:
A jury pool consists of 27 people. 11 people be chosen to serve on a jury and one additional person be chosen to serve as the jury foreman
Total of 27 people. 11 people can be selected from 27 people in 27C11 ways
one additional person be chosen to serve as the jury foreman
after selecting 11 people , remaining is 27 - 11= 16 people
Now 1 is selected from 16 in 16 ways
Number of different ways = 
