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umka21 [38]
2 years ago
7

Hector is dividing students into groups for a nature hike. He wants to divide the boys and girls so that each group has the same

number of both boys and girls. There are 21 boys and 56 girls signed up for the hike. Into how many groups can the students be divided? How many boys and how many girls will be in each group?
Mathematics
1 answer:
Zolol [24]2 years ago
5 0

Answer: The students can be divided into 7 groups.

Each group will have 3 boys and 8 girls.

Step-by-step explanation:

There are 21 boys and 56 girls.

To divide them so that each group has the same number of both boys and girls.

We find GCD(21,56).

21 = 3 x 7

56 = 2 x 2 x 2 x 7

GCD (21,56) = 7

So, the students can be divided into 7 groups.

Number of girls in each group = \dfrac{56}{7}=8

Number of boys in each group = \dfrac{21}{7}=3

So, each group will have 3 boys and 8 girls.

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Answer:

A number line going from 0 to 4.5 in increments of 0.5

Step-by-step explanation:

This solution makes the most sense because 4.5 and 2.5 both have a decimal of 0.5

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A retail store offers all television sets at 80%, or , of their original price if the customer buys a store membership for $100.
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Please help. A 32-pound box of cantaloupe costs 24.40. How much would a 12-pound box cost?
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Answer:

I believe it should be $9.15

Step-by-step explanation:

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If a pack of 24 pencils cost $2.35 how much does a single pencil cost
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2 years ago
A customer borrowed $2000 and then a further $1000 both repayable in 12 months. What should he have saved if he had taken out on
Neporo4naja [7]

Answer:

a. $60

Step-by-step explanation:  

We will use simple interest formula to solve our given problem.

A=P(1+rt), where

A= Amount after t years.

P= Principal amount.

r= Interest rate in decimal form.      

t= Time in years.

Let us find amount of loans repayable after 12 months for taking two amounts of $2000 and $1000.

As $2000 and $1000 are less than 2500, so the rate of loan will be 10%.

10\%=\frac{10}{100}=0.10

12 months = 1 year.

A=2000(1+0.10\times 1)

A=2000(1+0.10)

A=2000(1.10)

A=2200

Now let us find amount repayable after 12 months for borrowing $1000.

A=1000(1+0.10\times 1)

A=1000(1+0.10)

A=1000(1.10)

A=1100

Adding these amounts we will get total repayable amount after 12 months for borrowing $2000 and $1000 separately.

\text{Amount repayable for borrowing two separate amounts}=2200+1100=3300

Now let us find repayable amount after 12 months for taking 1 loan. As $3000 is between $2501 and $7500, so rate of loan will be 8%.

8\%=\frac{8}{100}=0.08

A=3000(1+0.08\times 1)

A=3000(1+0.08)

A=3000(1.08)

A=3240

Now let us find difference between both repayable loan amounts.

\text{Difference between both repayable loan amounts}=3300-3240

\text{Difference between both repayable loan amounts}=60

Therefore, the customer should have saved $60, if he had taken out one loan for $3000 and option a is the correct choice.

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2 years ago
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