You need to use the angle sum of a triangle in triangle CAD to express y in term of x
for triangla CAD , y = (180 -x) /2
180 = 3x + [ (180-x)/2]
x = 36
hope this helps
Hello there,
There is a total of 40 animals in that in 10 zebras, 10 lions, 10 elephants, and 10 monkeys.
So the probability of them both being lions is pretty rare. 2/40 so that would give you a 1/20 chance of both crackers being both lions.
I hope this helps!
Answer: Barbarino's rentals has a better deal.
She has to drive 887.5 miles to spend the same amount at either company.
Step-by-step explanation:
Hi, to answer this question we have to analyze the information given:
<em>Mr.kotters rentals (A)
</em>
- <em>$99 PER WEEK
</em>
- <em>$0.11per mile over 100 miles
</em>
<em>Barbarino's rentals (B)
</em>
- <em>$75 per week
</em>
- <em>$0.15 per mile over 150 miles
</em>
For "A"
Cost = 0.11 (432-100) + 99 = $135.52
For "B"
Cost= 0.15 (432-150) +75 = $117.3
Barbarino's rentals has a better deal, since $117.3(B) < $135.52 (A)
To find how many miles would Glenna drive before she would be spending the same amount at either company:
A =B
0.11 (M-100) + 99 =0.15 (M-150) +75 = $117.3
Solving for M (miles)
0.11 M -11+99 = 0.15 M -22.5+75
-11 +99 +22.5 -75 =0.15M -0.11 M
35.5 = 0.04M
35.5/0.04 = M
887.5 =M
She has to drive 887.5 miles to spend the same amount at either company.
<u>Answer:</u>
x = 4 (extraneous solution)
<u>Step-by-step explanation:</u>
This solution is extraneous. Reason being that even if it can be solved algebraically, it is still not a valid solution because if we substitute back 
, we will get two fractions with zero denominator which would be undefined.
