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Alex777 [14]
1 year ago
15

Translate the sentence into an equation. Use n for the number.

Mathematics
2 answers:
Butoxors [25]1 year ago
8 0

Answer:

27 = n-3

Step-by-step explanation:

n = 27+3

n = 30

Lyrx [107]1 year ago
4 0

Answer:

x-3 =27

Step-by-step explanation:

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Part A: Michael bought vegetables that weighs 4 and 1 over 8 pounds. How many ounces does the vegetables weigh? Show your work.
IgorLugansk [536]

Answer: 204 Ounces.

Step-by-step explanation:

76 + 1 6 x 8

8 0
1 year ago
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An element with mass 970 grams decays by 27.7% per minute. How much of the element is remaining after 13 minutes, to the nearest
11Alexandr11 [23.1K]
Every 1 minute, you multiply the mass by 27.7% or 0.277

after 1 minute, you multiply once
after 2 minutes, you multiply twice
3, thrice
etc
so after 13 minutes, you multiply 13 times or 0.277^13

so what is 970g *0.277^13 =?

7 0
2 years ago
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Turkey sandwiches cost $2.50 and veggie wraps cost $3.50 at a snack stand. Ben has sold no more than $30 worth of turkey sandwic
grigory [225]

<u>Answer:</u>

The maximum number of turkey sandwiches Ben could have sold is 6.

<u>Step-by-step explanation:</u>

We are given that turkey sandwiches cost $2.50 and veggie wraps cost $3.50 at a snack stand.

Given the information, we are to find the maximum value of turkey sandwiches Ben could have sold.

2 . 5 0 x + 3 . 5 0 y \leq 3 0

Number of veggie wraps sold (y) = 4

2.50x + 3.50(4) <   30

2.50x + 14          <   30

<u>           - 14               -14 </u>

2.50x                   <   16

x

x

The maximum number of turkey sandwiches Ben could have sold is 6.

4 0
2 years ago
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In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
7nadin3 [17]

Correct answer is: distance from D to AB is 6cm

Solution:-

Let us assume E is the altitude drawn from D to AB.

Given that m∠ACB=120° and ABC is isosceles which means

m∠ABC=m∠BAC = \frac{180-120}{2}=30

And AC= BC

Let AC=BC=x

Then from ΔACD , cos(∠ACD) = \frac{DC}{AC} =\frac{4}{x}

Since DCB is a straight line m∠ACD+m∠ACB =180

                                              m∠ACD = 180-m∠ACB = 60

Hence cos(60)=\frac{4}{x}

          x=\frac{4}{cos60}= 8

Now let us consider ΔBDE, sin(∠DBE) = \frac{DE}{DB} =\frac{DE}{DA+AB} = \frac{DE}{4+8}

DE = 12sin(30) = 6cm

7 0
2 years ago
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I can’t see it where is it it’s blurry
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