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Thepotemich [5.8K]
2 years ago
14

The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this yea

r actually decreased by 20 percent. What percent of the projected attendance was the actual attendance?
Mathematics
1 answer:
Gnom [1K]2 years ago
5 0

Answer: 64 %

Step-by-step explanation:

Assume attendance last year to be equal to "x"

- An increase in percentage sees us add the percentage amount to 100.

- A decrease in percentage sees us subtract the percentage amount from 100.

Projected attendance = ((100+25)/100) * x = 1.25x

Actual attendance = ((100-20)/100) * x = 0.80x

Hence ratio of a actual to projected attendance = 0.80x/1.25x = 0.64

Convert into percentage = 0.64 * 100 = 64 %

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Would apreciate if someone helped me..
PtichkaEL [24]

Answer:

a). x = 11

b). m∠DMC = 39°

c). m∠MAD = 66°

d). m∠ADM = 36°

e). m∠ADC = 18°

Step-by-step explanation:

a). In the figure attached,

m∠AMC = 3x + 6

and m∠DMC = 6x - 49

Since "in-center" of a triangle is a points where the bisectors of internal angles meet.

Therefore, MC is the angle bisector of angle AMD.

and m∠AMC ≅ m∠DMC

3x + 6 = 8x - 49

8x - 3x = 49 + 6

5x = 55

x = 11

b). m∠DMC = 8x - 49

                   = (8 × 11) - 49

                   = 88 - 49

                   = 39°

c). m∠MAD = 2(m∠DAC)

                   = 2(30)°

                   = 60°

d). Since, m∠AMD + m∠ADM + m∠MAD = 180°

    2(39)° + m∠ADM + 66° = 180°

    78° + m∠ADM + 66° = 180°

    m∠ADM = 180° - 144°

                   = 36°

e). m∠ADC = \frac{1}{2}(m\angle ADM)

                   = \frac{1}{2}(36)

                   = 18°

5 0
2 years ago
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B. x<2
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Answer:

Step-by-step explanation:

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S_A_V [24]

Answer:

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Well if there are 36 apples and there are 12 more apples then peaches then 36-12= 24 24/2=12 

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