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Thepotemich [5.8K]
2 years ago
14

The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this yea

r actually decreased by 20 percent. What percent of the projected attendance was the actual attendance?
Mathematics
1 answer:
Gnom [1K]2 years ago
5 0

Answer: 64 %

Step-by-step explanation:

Assume attendance last year to be equal to "x"

- An increase in percentage sees us add the percentage amount to 100.

- A decrease in percentage sees us subtract the percentage amount from 100.

Projected attendance = ((100+25)/100) * x = 1.25x

Actual attendance = ((100-20)/100) * x = 0.80x

Hence ratio of a actual to projected attendance = 0.80x/1.25x = 0.64

Convert into percentage = 0.64 * 100 = 64 %

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Answer:

A random sample of 100 male and females was selected. Let muf be the population mean number of hours spent playing online games for females and let mum be the population mean number of hours spent playing online games for males.

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2 years ago
The ordered pairs model an exponential function, where w is the function name and t is the input variable. {(1, 60), (2, 240), (
alexandr1967 [171]
We are given the set of points
<span>{(1, 60), (2, 240), (3, 960), (4, 3840)}{(1, 60), (2, 240), (3, 960), (4, 3840)} 
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PLZZ IN NEED HELP!
boyakko [2]

Answer:

18\pi\ cm^2

Step-by-step explanation:

step 1

Find the area of complete circle

The area of the circle is given by the formula

A=\pi r^{2}

we have

r=9\ cm

substitute

A=\pi (9)^{2}

A=81\pi\ cm^2

step 2

Find the area of the shaded region

we know that

The area of complete circle subtends a central angle of 360 degrees

so

using proportion

Find out the area of the shaded region if the central angle is equal to 80 degrees

\frac{81\pi}{360^o}=\frac{x}{80^o}\\\\x=81\pi(80)/360\\\\x= 18\pi\ cm^2

6 0
2 years ago
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